If the distance between the first and ninth minima of a double slit pattern is 1.2...

If the distance between the first and ninth minima of a double slit pattern is 1.2 mm and the slits are separated by 0.15 mm with the screen 60 cm from the slits, what is the wavelength of the light used? How will the distance change if the wavelength increased by 50 nm? What will be the change if is increased 5 times? How can we experience(see) the pattern? What is the change in photon energy in comparison to initial light?

Expert Solution

Consider double slit experiment pattern .The equations for double slit interference imply that a series of bright and dark lines are formed. For vertical slits, the light spreads out horizontally on either side of the incident beam into a pattern called interference fringes. The intensity of the bright fringes falls off on either side, being brightest at the center. The closer the slits are, the more is the spreading of the bright fringes. We can see this by examining the equation

d sin = m, for m = 0, 1, −1, 2, −2, . . . .

genius_generous answered 2 years ago

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