In: Physics
In the double-slit experiment of the figure below, the viewing screen is at distance D = 4.00 m, point P lies at distance y = 13.0 cm from the center of the pattern, the slit separation d is 4.50
The wave length of light ? = 650nm
the seperation between slits d = 4.50?m
the distance between screen D = 4.0m
the postion of point P is y = 13cm
(a) The position of P in terms of phase difference
? = 2?/? dsin?
=[ 2?/(650*10^-9)](4.5*10^-6)(y/D)
since for small angles sin? ? tan? = y/D
= 0.0435*10^3 (13*10^-2/4)
= 0.45? rad = 1.413 rad
(b) The ratio of intensity
I/I0 = 4cos^2(?/2)
= 4cos^2(1.413/2)
=2.3