In the double-slit experiment of the figure below, the viewing screen is at distance D =...

In the double-slit experiment of the figure below, the viewing screen is at distance D = 4.00 m, point P lies at distance y = 13.0 cm from the center of the pattern, the slit separation d is 4.50

Solutions

Expert Solution

The wave length of light ? = 650nm

the seperation between slits d = 4.50?m

the distance between screen D = 4.0m

the postion of point P is y = 13cm

(a) The position of P in terms of phase difference

? = 2?/? dsin?

=[ 2?/(650*10^-9)](4.5*10^-6)(y/D)

since for small angles sin? ? tan? = y/D

= 0.0435*10^3 (13*10^-2/4)

= 0.45? rad = 1.413 rad

(b) The ratio of intensity

I/I0 = 4cos^2(?/2)

= 4cos^2(1.413/2)

=2.3

genius_generous answered 5 months ago

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