Question

A beverage manufacturer produces a popular drink in 500 ml cans (0.5 litres). The drink is sold in cases containing 24 cans. To produce 1000 litres of the drink, 59 litres of a special ingredient is required. The remainder consists of water to which 200 kilograms of sugar is added (assume that sugar does not affect volume).

Write a program which accepts as input the number of cases of the drink that are required and calculates and displays the following:

• The amount of litres of the special ingredient required
• The amount of kilograms of sugar required
• The amount of water required

only use iostream library, no arrays

WRITTEN IN C++

Answer 1

Source Code:

#include <iostream>
using namespace std;

int main()
{
   float special_ingredient_per_litre=59/1000.0 ;
   float water_per_litre=(1000 - 59)/1000.0 ;
   float sugar_per_litre=200/1000.0 ;

   int no_of_cases=0;
   cout<<"Enter number of cases of drink is required: ";
   cin>>no_of_cases;

   int total_litres=no_of_cases*24*0.5 ;

   cout<<"The amount of litres of the special ingredient required: "<<total_litres*special_ingredient_per_litre<<endl;
   cout<<"The amount of kilograms of sugar required: "<<total_litres*sugar_per_litre<<endl;
   cout<<"The amount of water required: "<<total_litres*water_per_litre<<endl;
}