Question

Two parallel squared metal sheets (of 1 m length side) are separated by 1 mm of vacuum. The sheets are connected to a dc source with potential difference of 500V. What is the magnitude of charges accumulated on the sheets upon connection to the source?To solve this problem I needed to:

A. Use the equation E=V/d;

B. Calculate the Coulomb’s forces acting on the charges;

C. Figure out what a known device is represented by these sheets;

D. Calculate the capacitance of the voltage source;

E. Calculate the capacitance of the sheets;

F. Find the formula linking voltage and charge in capacitor;

G. A, B, and D;

H. C, E, and F.

PLEASE SHOW HOW TO DO CALCULATIONS

Answer 1

For this problem you need to

Figure out what a known device is represented by these sheets

Calculate the capacitance of the sheets;

Find the formula linking voltage and charge in capacitor

Answer is C E and F

Steps:

This represents a parallel plate capacitor. The capacitance of the parallel plate capacitor is

where A is the surface of the sheets and d is the separation between the sheets.

A = 1 x 1 = 1 m^2

d = 1mm = 0.001 m

epsilon0 = 8.85 x 10^-12 F/m is the free space permitivity.

The magnitude of the charge on each of the plates is given by the formula linking charge in the capacitor to the voltage

V = 500 V is the voltage between the plates

Plug in the values

Q = 4.425 x 10^-6 C

Unit of Q is Coulombs(C)

The charge on the positive plate is +Q and the negative plate is -Q.