Question

In: Physics

A parallel-plate capacitor has 2.18 cm2 plates that are separated by 5.69 mm with air between...

A parallel-plate capacitor has 2.18 cm2 plates that are separated by 5.69 mm with air between them. If a 18.0 V battery is connected to this capacitor, how much energy does it store?

Solutions

Expert Solution

DATA:

SOLUTION

The energy stored   by a parallel plate capacitor can be obtained using:

Where:

is the voltage on the capacitor.

is the capacitance, which is defined as:

Where:

is the permitivity of free space, which has a value of:

is the area of plates of the capacitor

is the distance between plates.

Now, first we need to find the capacitance , with the help of equation (2). Therefore, replacing (3) and data given values into equation (2) we have:

Solving we obtain:

Now, we can find the energy stored . Therefore,  inserting (5) and data given values into equation (1) we have:

Solving we obtain:


Related Solutions

A parallel-plate capacitor has an area of 5.00 cm2, and the plates are separated by 2.00 mm with...
A parallel-plate capacitor has an area of 5.00 cm2, and the plates are separated by 2.00 mm with air between them. The capacitor stores a charge of 500 pC.(a) What is the potential difference across the plates of the capacitor?1 V(b) What is the magnitude of the uniform electric field in the region between the plates?
An air-filled parallel-plate capacitor has plates of area 2.50 cm separated by 1.00 mm. The capacitor...
An air-filled parallel-plate capacitor has plates of area 2.50 cm2 separated by 1.00 mm. The capacitor is connected to a 24.0-V battery. (a) Find the value of its capacitance._______  pF (b) What is the charge on the capacitor? _______  pC (c) What is the magnitude of the uniform electric field between the plates? _______ V/m
The plates of an air-filled parallel-plate capacitor with a plate area of 15.0 cm2 and a...
The plates of an air-filled parallel-plate capacitor with a plate area of 15.0 cm2 and a separation of 8.95 mm are charged to a 170-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor. (a) What is the charge on the capacitor before and after the dielectric is inserted? Qi = C Qf = C (b) What is the capacitance of the capacitor after...
An air-filled parallel-plate capacitor has plates of area 2.40 cm^2 separated by 3.00 mm. The capacitor...
An air-filled parallel-plate capacitor has plates of area 2.40 cm^2 separated by 3.00 mm. The capacitor is connected to a(n) 23.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/C
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.00 mm. (a) If a 16.0 V potential difference is applied to these plates, calculate the electric field between the plates. kv/m (b) What is the surface charge density? nC/m2 (c) What is the capacitance? pF (d) Find the charge on each plate. pC
The parallel-plates in a capacitor, with a plate area 1.2×10−3 cm2 and an air-filled separation of...
The parallel-plates in a capacitor, with a plate area 1.2×10−3 cm2 and an air-filled separation of 10 mm, are charged by a 12 V battery. They are then disconnected from the battery and pushed together (without discharge) to a separation of 3.5 mm. (a) Find the initial potential difference between the plates and the initial stored energy. (6 points) (b) Find the final potential difference between the plates and the final stored energy. (6 points) (c) How much work is...
A parallel plate air capacitor with no dielectric between the plates is connected to a constant...
A parallel plate air capacitor with no dielectric between the plates is connected to a constant voltage source. How would the capacitance and the charge change if a dielectric of dielectric constant K=2 is inserted between the plates. C0 and Q0 are the capacitance and charge of the capacitor before the introduction of the dielectric.
A parallel-plate capacitor with plates of area 590 cm2 and is connected across the terminals of...
A parallel-plate capacitor with plates of area 590 cm2 and is connected across the terminals of a battery. After some time has passed, the capacitor is disconnected from the battery. When the plates are then moved 0.48 cm farther apart, the charge on each plate remains constant but the potential difference between the plates increases by 100 V. (a) What is the magnitude of the charge on each plate? (b) Do you expect the energy stored in the capacitor to...
Problem 2 – The plates of a parallel-plate capacitor are separated by a distance d =...
Problem 2 – The plates of a parallel-plate capacitor are separated by a distance d = 0.2 m. There is vacuum between the plates. The voltage difference between the plates is 150 V. The capacitance of the plates is 3 μF. a) (6 pts) Find the magnitude of the electric field between the plates (ignoring edge effects). b) (12 pts) An alpha particle, which is doubly ionized helium, He2+ (charge = 2e where e is the elementary charge, mass =...
Parallel-plates in a capacitor, with area 1.2×10−3 cm2 and air-filled separation of 10 mm, are charged...
Parallel-plates in a capacitor, with area 1.2×10−3 cm2 and air-filled separation of 10 mm, are charged by a 12 V battery. They are disconnected from the battery and pushed together (with no discharge) to a separation of 3.5 mm. a) Find the initial and final potential difference between the plates and the initial and final stored energy b) How much work is required to decrease the separation between the plates and where does this work come from? c) After the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT