In: Statistics and Probability
In the book Advanced Managerial Accounting, Robert P.
Magee discusses monitoring cost variances. A cost variance
is the difference between a budgeted cost and an actual cost. Magee
describes the following situation:
Michael Bitner has responsibility for control of two
manufacturing processes. Every week he receives a cost variance
report for each of the two processes, broken down by labor costs,
materials costs, and so on. One of the two processes, which we'll
call process A , involves a stable, easily controlled
production process with a little fluctuation in variances. Process
B involves more random events: the equipment is more
sensitive and prone to breakdown, the raw material prices fluctuate
more, and so on.
"It seems like I'm spending more
of my time with process B than with process A,"
says Michael Bitner. "Yet I know that the probability of an
inefficiency developing and the expected costs of inefficiencies
are the same for the two processes. It's just the magnitude of
random fluctuations that differs between the two, as you can see in
the information below."
"At present, I investigate
variances if they exceed $2,931, regardless of whether it was
process A or B. I suspect that such a policy is
not the most efficient. I should probably set a higher limit for
process B."
The means and standard deviations of the cost variances of
processes A and B, when these processes are in
control, are as follows: (Round probability answers to 4
decimal places.):
Process A | Process B | |
Mean cost variance (in control) | $ 0 | $ 0 |
Standard deviation of cost variance (in control) | $5,271 | $10,270 |
Furthermore, the means and standard deviations of the cost
variances of processes A and B, when these
processes are out of control, are as follows:
Process A | Process B | |
Mean cost variance (out of control) | $7,400 | $ 7,381 |
Standard deviation of cost variance (out of control) | $5,271 | $10,270 |
(a) Recall that the current policy is to investigate a cost variance if it exceeds $2,931 for either process. Assume that cost variances are normally distributed and that both Process A and Process B cost variances are in control. Find the probability that a cost variance for Process A will be investigated. Find the probability that a cost variance for Process B will be investigated. Which in-control process will be investigated more often.
Process A | ||
Process B | ||
(Click to select)Process AProcess B is investigated more often
(b) Assume that cost variances are normally
distributed and that both Process A and Process B
cost variances are out of control. Find the probability that a cost
variance for Process A will be investigated. Find the
probability that a cost variance for Process B will be
investigated. Which out-of-control process will be investigated
more often.
Process A | ||
Process B | ||
(Click to select)Process BProcess A is investigated more often.
(c) If both Processes A and B
are almost always in control, which process will be investigated
more often.
(Click to select)Process AProcess B will be investigated more
often.
(d) Suppose that we wish to reduce the probability
that Process B will be investigated (when it is in
control) to .2891. What cost variance investigation policy should
be used? That is, how large a cost variance should trigger an
investigation? (Round your final answer to the nearest
whole number.)
Using this new policy, what is the probability that an out-of-control cost variance for Process B will be investigated? (Round your final answer to four decimal places.)
Cost variance | |
Probability that an out-of-control cost variance for Process B will be investigated | |
First, let's frame the problem from a statistical viewpoint.
There are two processes A and B for a random variable cost variance. The two processes are described using the given means and variances for the cases when the cost variances are in control and out of control. Let us denote the parameters (mean and standard deviation) for the different conditions for A and B as described below -:
Condition | Mean | Standard Deviation |
Process A in control | ||
Process A out of control | ||
Process B in control | ||
Process B out of control |
Now, since it is given that we can assume cost variances to be distributed normally -:
(a) The probability that process A (when in control) is investigated, is essentially the probability of a random variable where This probability can be evaluated using the standard normal CDF table , where Z is a gaussian random variable with 0 mean and a standard deviation of 1. Since when A is in control,
One can look up the values in the standard normal CDF table to find , which turns out to be 0.2912. To find the probabilities using standard normal CDF tables, use the fact that the gaussian PDF is symmetric and that the total area under the curve is 1. Hence, if the table gives an area from 0 to x (let that area be , then . Using the similar steps, the probability that the process B (when in control) is investigated is :
Hence, as the probability of process B being investigated ( 0.3897) is greater than process A being investigated (0.2912) when both the processes are in control, we can say that process B will be investigated more often.
(b) now since the processes are out of control, we use the same approach as in part (a), with the means and standard deviations corresponding to the out of control case for processes A and B. Therefore,
Hence Probability of Process A being investigated in out of control situation is 0.7995. Similarly, for process B, we get
is a random variable analogous to , i.e for the controlled case.
Hence for this case, since the probability of process A being investigated is higher, it will be investigated more often as compared to process B.
(c) Already answered in part (a), that process B will be more likely to get investigated.
(d) Let the process B is now investigated if cost variance is greater than . Using the expressions above, we can write that
Using the fact that , we get that . Using the inverse table we get that x is closest to 0.56 in the look-up table. Hence,
or in other words, , which is almost 5751 dollars. Hence the probability of an out of control process B investigated with this new policy is :
Note that these answers are slightly approximate due to the least count of the standard normal table.