In: Chemistry
1 mole of K4[Fe(CN)6] contains carbon = 6g atoms. 0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms. The mass of carbon present in 0.5 mole of K4[Fe(CN)6] is:
From the question
Given-
1 mole of K4[Fe(CN)6] contain carbon = 6g atoms
Therefore,
0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms
Hence,
Mass of carbon in grams = (12g) × [(3g atoms )/(1g atom )] = (12g) × [(3g)/(1g)] =36g
So the the mass of carbon present in 0.5 moles of K4[Fe(CN)6] = 36g
The mass of carbon present is 36g