1 mole of K4[Fe(CN)6] contains carbon = 6g atoms. 0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms

1 mole of K4[Fe(CN)6] contains carbon = 6g atoms. 0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms. The mass of carbon present in 0.5 mole of K4[Fe(CN)6] is:

Expert Solution

From the question

Given-

1 mole of K4[Fe(CN)6] contain carbon = 6g atoms

Therefore,

0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms

Hence,

Mass of carbon in grams = (12g) × [(3g atoms )/(1g atom )] = (12g) × [(3g)/(1g)] =36g

So the the mass of carbon present in 0.5 moles of K4[Fe(CN)6] = 36g

The mass of carbon present is 36g

Nikhil Thakur answered 2 years ago

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1 mole of K4[Fe(CN)6] contains carbon = 6g atoms. 0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms

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