Question

Iron (Fe) is element 26 on the periodic table. A sample contains 6.50×10²⁴ atoms of Fe. Calculate the amount of Fe.

mol Fe

Answer 1

1 mole of Iron(Fe) weighs -----> 55.84 g/mol.

1 mole of Iron(Fe) contains ----> 6.023*10^23 atoms of Iron.

Conclusion:

6.023*10^23 atoms of Iron weighs ---> 55.84 g

6.50*10^24 atoms of Iron weighs -----> 55.84*6.50*10^24/(6.023*10^23)

                                                        = 602.62 g of Iron.

In mole:

6.023*10^23 atoms of Iron is equal to ----> 1 mole of Iron

6.50*10^24 atoms of Iron is equal to ------> 1*6.50*10^24/(6.023*10^23)

                                                               = 10.79 moles of Iron.