Question
In: Advanced Math
y'' - 4y' + 4y = e^2t + 2e^-2t + 14t^4 - sin2t + cost +...
y'' - 4y' + 4y = e^2t + 2e^-2t + 14t^4 - sin2t + cost + te^16t
Please solve for the particular solution. Do not find for coefficients.
Solutions
Colby Messinger answered 2 years agoRelated Solutions
Find the general solution of the differential equation y'' + 4y' + 4y = (e-2t/t2)
Find the general solution of the differential equation y'' + 4y'
+ 4y = (e-2t/t2)
y''+4y'+4y=2e^{-2x} Find general solution.
y''+4y'+4y=2e^{-2x} Find general solution.
Find the particular solution to the equation. y''-4y'+5y=(e^(2t))(sec(t))
Find the particular solution to the equation.
y''-4y'+5y=(e^(2t))(sec(t))
Find the particular solution: y″−4y′+4y=(−11.5e^(2t))/(t^(2)+1)
Find the particular solution:
y″−4y′+4y=(−11.5e^(2t))/(t^(2)+1)
Find a particular solution to y” + 4y = 16t sin(2t)
Find a particular solution to
y” + 4y = 16t sin(2t)
Solve using judicious guessing. y''+4y = t*sin(2t)
Solve using judicious guessing.
y''+4y = t*sin(2t)
Solve y′′ + 4y′ + 3y = 15e^2t given y(0) = −7,y′(0) = 16 by the...
Solve y′′ + 4y′ + 3y = 15e^2t given y(0) = −7,y′(0) = 16 by the
method of Laplace transforms.
Find a particular solution to y′′+4y′+4y=(e^−2x)/x^4 using variation of parameters yp= ?
Find a particular solution to y′′+4y′+4y=(e^−2x)/x^4 using
variation of parameters
yp= ?
Solve the following initial value: y ''+ 4y = 2 cos 2t, y(0) = −2 and...
Solve the following initial value: y ''+ 4y = 2 cos
2t, y(0) = −2 and y 0 (0) = 0
Question : y'''+4y' =0 , y'''-2y''+4y'-8y=0 , y'''-3y''+3y'-y=0 , y^4 -4y'''+6y''-4y+y=0 , y^4+6y''+9y=0 , y^6+y'''=0
Question : y'''+4y' =0 , y'''-2y''+4y'-8y=0 , y'''-3y''+3y'-y=0
, y^4 -4y'''+6y''-4y+y=0 , y^4+6y''+9y=0 , y^6+y'''=0
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