Find the particular solution to the equation. y''-4y'+5y=(e^(2t))(sec(t))

Find the particular solution to the equation.

y''-4y'+5y=(e^(2t))(sec(t))

Expert Solution

milcah answered 1 year ago

Find the general solution of the differential equation y'' + 4y' + 4y = (e-2t/t2)

Find the particular solution: y″−4y′+4y=(−11.5e^(2t))/(t^(2)+1)

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find the general solution of y'''-4y''+5y'=e^x

y'' - 4y' + 4y = e^2t + 2e^-2t + 14t^4 - sin2t + cost +...

y'' - 4y' + 4y = e^2t + 2e^-2t + 14t^4 - sin2t + cost + te^16t Please solve for the particular solution. Do not find for coefficients.

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Find a particular solution to the non-homogeneous differential equation: (a) y'' − 4y = 4t^2 (b) y '' − 4y = sin(2t) (c) y '' + 4y = sin(2t) (d) y '' + y = cos(t)

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