Find a particular solution to y” + 4y = 16t sin(2t)

Find a particular solution to

y” + 4y = 16t sin(2t)

Expert Solution

Colby Messinger answered 1 month ago

Find the particular solution: y″−4y′+4y=(−11.5e^(2t))/(t^(2)+1)

Find the particular solution to the equation. y''-4y'+5y=(e^(2t))(sec(t))

Find the general solution of the differential equation y'' + 4y' + 4y = (e-2t/t2)

find the particular solution for: y'' - 4y' - 12y = e2x(-3x2 + 4x + 5)...

find the particular solution for: y'' - 4y' - 12y = e2x(-3x2 + 4x + 5) (hint: try y= ue2x then use: u = Ax2 + Bx + C)

FIND THE GENERAL SOLUTION TO THE DE: Y”’ + 4Y” – Y’ – 4Y = 0...

FIND THE GENERAL SOLUTION TO THE DE: Y”’ + 4Y” – Y’ – 4Y = 0 COMPUTE: L {7 e 3t – 5 cos ( 2t ) – 4 t 2 } COMPUTE: L – 1 {(3s + 6 ) / [ s ( s 2 + s – 6 ) ] } SOLVE THE INITIAL VALUE PROBLEM USING LAPLACE TRANSFORMS: Y” + 6Y’ + 5Y = 12 e t WHEN : f ( 0 ) = -...

y'' - 4y' + 4y = e^2t + 2e^-2t + 14t^4 - sin2t + cost +...

y'' - 4y' + 4y = e^2t + 2e^-2t + 14t^4 - sin2t + cost + te^16t Please solve for the particular solution. Do not find for coefficients.

Find a particular solution to y′′+4y′+4y=(e^−2x)/x^4 using variation of parameters yp= ?

For each of the following equations, find the general solution: (x^2)y′′+xy′+ 4y= sin(lnx) + sin(2 lnx)...

For each of the following equations, find the general solution: (x^2)y′′+xy′+ 4y= sin(lnx) + sin(2 lnx) y′′+y=tcost Thank you!

y''+4y'+4y=2e^{-2x} Find general solution.

Find a particular solution to the non-homogeneous differential equation: (a) y'' − 4y = 4t^2 (b)...

Find a particular solution to the non-homogeneous differential equation: (a) y'' − 4y = 4t^2 (b) y '' − 4y = sin(2t) (c) y '' + 4y = sin(2t) (d) y '' + y = cos(t)

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