In this question first I find the complementary solution and
then find the particular solution of the given differential
equation. Hope you understand the solution.
1. Find the general solution to the following ODE:
y′′′+ 4y′= sec(2x)
2. Find the solution to the following IVP:
2y′′+ 2y′−2y= 6x2−4x−1
y(0) = −32
y′(0) = 5
3. Verify that y1=x1/2ln(x) is a solution
to
4x2y′′+y= 0,
and use reduction of order to find a second solution
y2.
4.
Find the general solutions to the following ODEs:
a) y′′′−y′= 0.
b) y′′+ 2y′+y= 0.
c) y′′−4y′+ 13y= 0.
FIND THE GENERAL SOLUTION TO THE DE: Y”’ + 4Y” – Y’ –
4Y = 0
COMPUTE:
L {7 e 3t – 5 cos ( 2t ) – 4 t 2
}
COMPUTE:
L – 1 {(3s + 6 ) / [ s ( s 2 + s – 6 ) ]
}
SOLVE THE INITIAL VALUE PROBLEM USING LAPLACE
TRANSFORMS:
Y” + 6Y’ + 5Y = 12 e t
WHEN : f ( 0 ) = -...
x2 y" + (x2+x) y’
+(2x-1) y = 0,
Find the general solution of y1 with
r1 and calculate the coefficient up to
c4 and also find the general expression of the
recursion formula, (recursion formula for
y1)
Find the general solution of y2 based on
theorem 4.3.1. (Hint, set d2 = 0)