Question

In: Statistics and Probability

A researcher wants to investigate different formats for taking an exam.

SHOW ANY WORK

Computational problems:

One-way ANOVA

A researcher wants to investigate different formats for taking an exam. She randomly assigns one-third of the class to an open book exam, one-third to no notes, and one-third to one page of notes only. The data appear below.

  1.       What is the F statistic reported in appropriate APA style?
  1.       What is your decision? (use alpha = .05)
  1.       Do you need to conduct a follow-up test?
  1.       Do you need to determine the effect size? If yes, what are the results?

          Open book                  No notes            One page only

          65                        88                        70

          70                        94                        72

          72                         89                        76

          78                        98                        80

          82                        93                        81

          79                        94                        82

Solutions

Expert Solution

treatment A B C D
count, ni = 6 6 6
mean , x̅ i = 74.333 92.67 76.833
std. dev., si = 6.408 3.670 4.997
sample variances, si^2 = 41.067 13.467 24.967
total sum 446 556 461 1463 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   81.28
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 48.225 129.707 19.753
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 289.352 778.241 118.519 1186.111111
SS(within ) = SSW = Σ(n-1)s² = 205.333 67.333 124.833 397.5000

no. of treatment , k =   3
df between = k-1 =    2
N = Σn =   18
df within = N-k =   15
  
mean square between groups , MSB = SSB/k-1 =    593.0556
  
mean square within groups , MSW = SSW/N-k =    26.5000
  
F-stat = MSB/MSW =    22.3795

anova table
SS df MS F p-value F-critical
Between: 1186.1111 2 593.056 22.379 0.0000 3.682
Within: 397.5000 15 26.500
Total: 1583.6111 17
α = 0.05

F(2,15) = 22.379

   Decision:   p-value<α , reject null hypothesis    

yes, we need to conduct follow up test to check which pairs of means are significantly different

eta square ,effect size = SSbet/SST = 0.7490


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