Question
In: Civil Engineering
Design a set of activated sludge aeration tanks. The flow rate to treat is 5.6 MGD...
Design a set of activated sludge aeration tanks. The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The design solids concentration (X) at steady-state is 2,000 mg/l. The design MCRT is 7 days. The kinetic coefficients are as follows: K = 2 g BODg cells⋅d, Ks = 25 BOD/L, Kd = 0.06 day-1, Y = 0.5 g BODg cells⋅d. The influent ammonia concentration is 40 mg/l and nitrification is needed. It takes 1400 ft3of air per pound of BOD. Use rectangular tanks with a depth of 12 ft, a length to width ratio of 6 to 1, and a maximum length of 110 ft. Determine the following:
a) The hydraulic retention time (hr)
b) The steady-state effluent BOD concentration (mg/L)
c) The number of tanks and their lengths (ft) and widths (ft)
d) The air requirement (ft3/min)
Solutions
Ally Wells answered 1 week agoRelated Solutions
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A completely mixed activated sludge process is to be used to
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of BOD5. Use the following design criteria:
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b. MLVSS (X) = 3500 mg/L
c. Reactor depth = 11 ft
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Design an aeration tank for activated sludge wastewater treatment designed to meet an effluent standard of...
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m3/min with a primary effluent BOD5 of 250
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what is the rate limiting element in activated sludge design?
what is the rate limiting element in activated sludge
design?
Why aeration is important for activated sludge process? What would be the effect on the DO...
Why aeration is important for activated sludge process? What
would be the effect on the DO profile with time (provide a sketch)
and BOD removal and sludge production if:
Pumping more air than the required amount
An activated sludge process with an aeration basin volume of 0.3 MG is treating wastewater with...
An activated sludge process with an aeration basin volume of 0.3
MG is treating wastewater with the average daily flow of 2 MGD. The
raw sewage entering the treatment plant has an average BOD5 of 400
mg/L. The primary treatment removes 25% of BOD5 and the subsequent
activated sludge process is designed to remove 90% of BOD5.
Given:
Plant effluent BOD5 concentration = 30 mg/L
Biomass concentration in the aeration tank = 2,000 mg/L
Biomass concentration in the plant effluent...
Two types of flow regime are normally used in the design of an activated sludge process,...
Two types of flow regime are normally used in the design of an
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Q = 550 m3/d t = 6 hours Co = 225 mg/L k = 0.15 d-1
An activated sludge plant receive 5.0 MGD of wastewater with a BOD of 220 mg/L. The...
An activated sludge plant receive 5.0 MGD of wastewater with a
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activated sludge treatment processes (secondary BOD removal), (b)
aeration tank volume,...
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A conventional activated-sludge plant treats 10.0 MGD of municipal wastewater with a BOD concentration of 240...
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suspended solids of 200 mg/l. The sludge flow pattern is shown in
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