Given the equation: PCl3(g) + Cl2(g) ⇌ PCl5(g) kp = 1.05 at 70.5 °C If one...

Given the equation:

PCl3(g) + Cl2(g) ⇌ PCl5(g) kp = 1.05 at 70.5 °C

If one starts with 1,7 atm of PCl5(g), what is the partial pressure of PCl5(g) at equilibrium?

Solutions

Expert Solution

PCl3(g) + Cl2(g) ⇌ PCl5(g)

I 0 0 1.7

C +x +x -x

E +x +x 1.7-x

Kp = P_PCl5/P_PCl3 P_Cl2

1.05 = 1.7-x/x*x

1.05x^2 = 1.7-x

x = 0.88

P_PCl5 = 1.7-x = 1.7-0.88 = 0.82atm>>>>answer

queen_honey_blossom answered 1 year ago

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