FIND THE GENERAL SOLUTION TO THE DE: Y”’ + 4Y” – Y’ –
4Y = 0
COMPUTE:
L {7 e 3t – 5 cos ( 2t ) – 4 t 2
}
COMPUTE:
L – 1 {(3s + 6 ) / [ s ( s 2 + s – 6 ) ]
}
SOLVE THE INITIAL VALUE PROBLEM USING LAPLACE
TRANSFORMS:
Y” + 6Y’ + 5Y = 12 e t
WHEN : f ( 0 ) = -...
Find the general solution to the differential equation below.
y′′ − 6y′ + 9y = 24t−5e3
Calculate the inverse Laplace transform of ((3s-2)
e^(-5s))/(s^2+4s+53)
Calculate the Laplace transform of y = cosh(at) using the
integral definition of the Laplace transform. Be sure to note any
restrictionson the domain of s. Recall that cosh(t)
=(e^t+e^(-t))/2