Question

In: Statistics and Probability

A record of violent crimes for a random sample of cities from the list of U.S....

A record of violent crimes for a random sample of cities from the list of U.S. cities with the fewest crimes is shown below. At significance level 0.05, is there sufficient evidence to indicate a relationship between the city and the type of crime committed? (Contingency table )

Forcible Rape

Robbery

Aggravated assault

Cary, NC

14

35

70

Amherst, NY

10

33

76

Simi Valley, CA

14

37

77

Norman, OK

47

36

53

Solutions

Expert Solution

Claim: There is a relationship between the city and the type of crime committed.

The null and alternative hypothesis is

H0: There is no relationship between the city and the type of crime committed.

H1: There is a relationship between the city and the type of crime committed.

Level of significance = 0.05

Test statistic is

O: Observed frequency
E: Expected frequency.
E = ( Row total*Column total) / Grand total

Robbery Aggravated assault
Forcible Rape Total
Cary, NC 14 35 70 119
Amherst, NY 10 33 76 119
Simi Valley, CA 14 37 77 128
Norman, OK 47 36 53 136
Total 85 141 276 502
O E (O-E) (O-E)^2 (O-E)^2/E
14 20.1494 -6.1494 37.81515 1.876738
35 33.4243 1.575697 2.482822 0.074282
70 65.42629 4.573705 20.91878 0.31973
10 20.1494 -10.1494 103.0104 5.112329
33 33.4243 -0.4243 0.180033 0.005386
76 65.42629 10.57371 111.8032 1.708843
14 21.67331 -7.67331 58.87964 2.716689
37 35.95219 1.047809 1.097903 0.030538
77 70.3745 6.625498 43.89722 0.623766
47 23.02789 23.97211 574.6621 24.95505
36 38.1992 -2.1992 4.836495 0.126612
53 74.77291 -21.7729 474.0595 6.339991
Total 43.89

Degrees of freedom = ( Number of rows - 1 ) * ( Number of column - 1) = ( 4 - 1) * (3 - 1) = 3 * 2 = 6

Critical value = 12.592

( From chi-square table)

Test statistic > critical value we reject null hypothesis.

Conclusion:

There is a relationship between the city and the type of crime committed.


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