Question

In: Statistics and Probability

A random sample of n1 = 10 regions in New England gave the following violent crime...

A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.3 4.5 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. (i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to three decimal places.) x1 = s1 = x2 = s2 = (ii) Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use α = 0.01. (a) What is the level of significance? State the null and alternate hypotheses. H0: μ1 = μ2; H1: μ1 < μ2 H0: μ1 < μ2; H1: μ1 = μ2 H0: μ1 = μ2; H1: μ1 ≠ μ2 H0: μ1 = μ2; H1: μ1 > μ2 (b) What sampling distribution will you use? What assumptions are you making? The standard normal. We assume that both population distributions are approximately normal with known standard deviations. The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations. The Student's t. We assume that both population distributions are approximately normal with known standard deviations. What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.) (c) Find (or estimate) the P-value. P-value > 0.250 0.125 < P-value < 0.250 0.050 < P-value < 0.125 0.025 < P-value < 0.050 0.005 < P-value < 0.025 P-value < 0.005 Sketch the sampling distribution and show the area corresponding to the P-value. Maple Generated Plot Maple Generated Plot Maple Generated Plot Maple Generated Plot (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α? At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant. (e) Interpret your conclusion in the context of the application. Fail to reject the null hypothesis, there is sufficient evidence that violent crime in the Rocky Mountain region is higher than in New England. Reject the null hypothesis, there is sufficient evidence that violent crime in the Rocky Mountain region is higher than in New England. Fail to reject the null hypothesis, there is insufficient evidence that violent crime in the Rocky Mountain region is higher than in New England. Reject the null hypothesis, there is insufficient evidence that violent crime in the Rocky Mountain region is higher than in New England. Need Help

Solutions

Expert Solution

x1 x2
3.3 3.7
3.7 4.3
4.2 4.5
3.9 5.3
3.3 3.3
4.1 4.8
1.8 3.5
4.8 2.4
2.9 3.1
3.1 3.5
5.2
2.8
3.51 3.867 Average
0.832 0.943 Stdev

for mean use Excel function =AVERAGE(data)

for standard dev = STDEV.S(data)

=======================================

=======================================

=======================================

H0: μ1 = μ2

H1: μ1 < μ2

The reason is this sentence- Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England

=======================================

The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations.

========================================

================================================

c) P-value = T.DIST(-0.931,20,1) = 0.1815-----------(Excel function)

  0.125 < P-value < 0.250

=================================================

d) fail to reject the null hypothesis , data is not statistically significant at α= 0.01

  we fail to reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level

================================================

e) Fail to reject the null hypothesis, there is insufficient evidence that violent crime in the Rocky Mountain region is higher than in New England.


Related Solutions

A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.9 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.1 4.5 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.9 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.9 4.1 4.5 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population) x1: New England Crime Rate 3.5 3.7 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.9 4.3 4.5 5.1 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.5 3.7 4.0 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.3 4.7 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.0 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.3 4.7 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.4 3.6 4.0 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.8 4.5 4.4 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.5 3.9 4.0 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.7 4.3 4.5 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 x1 = 3.55 s1 = .83...
A random sample of n1 = 10 regions in New England gave the following violent crime...
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.5 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.1 4.5 5.3 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution...
A random sample of n1 = 10 winter days in Denver gave a sample mean pollution...
A random sample of n1 = 10 winter days in Denver gave a sample mean pollution index x1 = 43. Previous studies show that σ1 = 21. For Englewood (a suburb of Denver), a random sample of n2 = 12 winter days gave a sample mean pollution index of x2 = 36. Previous studies show that σ2 = 13. Assume the pollution index is normally distributed in both Englewood and Denver. (a) Do these data indicate that the mean population...
3) A random sample of ?? = 11 in Chicago gave the following information concerning violent...
3) A random sample of ?? = 11 in Chicago gave the following information concerning violent crime rates (per million population): ?? = 3.42 and ?? = 0.79. Another random sample of ?? = 14 in Las Vegas gave the following information concerning violent crime rates: ?? = 3.77 and ?? = 0.92. Do the data indicate that violent crime rate in Chicago is higher than that in Las Vegas? Use a 1% level of significance. Step One: State the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT