In: Statistics and Probability
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population).
x1: New England Crime Rate
3.3 | 3.9 | 4.2 | 4.1 | 3.3 | 4.1 | 1.8 | 4.8 | 2.9 | 3.1 |
Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population).
x2: Rocky Mountain Crime Rate
3.7 | 4.1 | 4.5 | 5.5 | 3.3 | 4.8 | 3.5 | 2.4 | 3.1 | 3.5 | 5.2 | 2.8 |
Assume that the crime rate distribution is approximately normal in both regions.
(i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to three decimal places.)
x1 | = |
s1 | = |
x2 | = |
s2 | = |
(ii) Do the data indicate that the violent crime rate in the Rocky
Mountain region is higher than in New England? Use α =
0.01.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: μ1 = μ2; H1: μ1 > μ2H0: μ1 < μ2; H1: μ1 = μ2 H0: μ1 = μ2; H1: μ1 ≠ μ2H0: μ1 = μ2; H1: μ1 < μ2
(b) What sampling distribution will you use? What assumptions are
you making?
The standard normal. We assume that both population distributions are approximately normal with known standard deviations.The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations. The Student's t. We assume that both population distributions are approximately normal with known standard deviations.The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations.
What is the value of the sample test statistic? (Test the
difference μ1 − μ2. Round
your answer to three decimal places.)
(c) Find (or estimate) the P-value.
P-value > 0.2500.125 < P-value < 0.250 0.050 < P-value < 0.1250.025 < P-value < 0.0500.005 < P-value < 0.025P-value < 0.005
Sketch the sampling distribution and show the area corresponding to
the P-value.
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis? Are the data statistically
significant at level α?
At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant.At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
(e) Interpret your conclusion in the context of the
application.
Fail to reject the null hypothesis, there is insufficient evidence that violent crime in the Rocky Mountain region is higher than in New England.Reject the null hypothesis, there is insufficient evidence that violent crime in the Rocky Mountain region is higher than in New England. Fail to reject the null hypothesis, there is sufficient evidence that violent crime in the Rocky Mountain region is higher than in New England.Reject the null hypothesis, there is sufficient evidence that violent crime in the Rocky Mountain region is higher than in New England.
i)
x1 =3.550
s1 =0.851
x2 =3.867
s2 =0.966
ii) level of significance =0.01
H0: μ1 = μ2; H1: μ1 < μ2
.The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations.
x1 = | 3.550 | x2 = | 3.867 |
s1 = | 0.851 | s2 = | 0.966 |
n1 = | 10 | n2 = | 12 |
Point estimate =x1-x2= | -0.317 |
std error =√(S21/n1+S22/n2)= | 0.3877 | |
test stat t =(x1-x2-Δo)/Se = | -0.817 |
0.125 < P-value < 0.250
d)
.At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
e)
Fail to reject the null hypothesis, there is insufficient evidence that violent crime in the Rocky Mountain region is higher than in New England