In: Statistics and Probability
In testing a new drug, we obtained the following results:
| Placebo | Drug A | Drug B | Drug C | 
|---|---|---|---|
| 3 | 5 | 6 | 7 | 
| 0 | 4 | 3 | 6 | 
| 2 | 2 | 4 | 5 | 
| 0 | 2 | 3 | 4 | 
| 0 | 2 | 4 | 3 | 
Run the ANOVA and fill in the summary table with the results obtained:
| SS | df | MS | F-ratio | p-value | |
| Between | 3 | ||||
|---|---|---|---|---|---|
| Within | 16 | ||||
| TOTAL | 19 | 
(Report P-value & F-ratio accurate to 3 decimal places and all other values accurate to 2 decimal places.)
What conclusion can be drawn at the 0.01 significance level?
The null and alternative hypothesis is

H1: At least one of the mean is different.
Level of significance = 0.01
By using excel we can solve this question easily.
First, enter all data into excel.
Click on Data -------> Data Analysis--------> Anova:
Single-Factor-----> Input Data -------> Select all data
-------> Output Range : Select any empty cell -------->
ok
We get

P-value = 0.003
P-value < 0.01 we reject null hypothesis.
Conclusion: