In: Statistics and Probability
In testing a new drug, we obtained the following results:
Placebo | Drug A | Drug B | Drug C |
---|---|---|---|
3 | 5 | 6 | 7 |
0 | 4 | 3 | 6 |
2 | 2 | 4 | 5 |
0 | 2 | 3 | 4 |
0 | 2 | 4 | 3 |
Run the ANOVA and fill in the summary table with the results obtained:
SS | df | MS | F-ratio | p-value | |
Between | 3 | ||||
---|---|---|---|---|---|
Within | 16 | ||||
TOTAL | 19 |
(Report P-value & F-ratio accurate to 3 decimal places and all other values accurate to 2 decimal places.)
What conclusion can be drawn at the 0.01 significance level?
The null and alternative hypothesis is
H1: At least one of the mean is different.
Level of significance = 0.01
By using excel we can solve this question easily.
First, enter all data into excel.
Click on Data -------> Data Analysis--------> Anova:
Single-Factor-----> Input Data -------> Select all data
-------> Output Range : Select any empty cell -------->
ok
We get
P-value = 0.003
P-value < 0.01 we reject null hypothesis.
Conclusion: