In: Statistics and Probability
Consider the following data for the patients taking the drug (Ascorbic Acid).
Placebo | Drug | Sum | |
Cold | 36 | 87 | 123 |
NoCold | 224 | 333 | 557 |
Sum | 260 | 420 | 680 |
What is the probability that a patient has No Cold? Is this a marginal or joint probability?
a) 0.18 marginal
b) 0.62 marginal
c) 0.82 marginal
d) 0.82 joint
e) 0.86 joint
Question 15
What is the probability that a patient is taking Placebo and has No Cold? Is this a marginal or joint probability?
a) 0.86 joint
b) 0.33 joint
c) 0.33 marginal
d) 0.82 marginal
e) 0.82 joint
Question 16
What is the probability that a patient is taking Placebo or has No Cold and identify the correct formula for this kind of probability?
a) 0.92 F5c
b) 0.87 F5a
c) 0.33 F5c
d) 0.92 F5b
e) 0.87 F5b
Question 17
Find conditional probability P(No Cold | taking the drug), P(No Cold | taking Placebo), P(taking drug | No Cold) and identify the correct formula for this kind of probability?
a) 0.49, 0.33, 0.82 F5ef
b) 0.18, 0.62, 0.82 F5c
c) 0.6, 0.71, 0.79, F5ef
d) 0.79, 0.86, 0.6 F5g
e) 0.79, 0.86, 0.6 F5ef
Question 18
Based on answers to previous questions the row and column variables are ________ (a) independent (b) dependent (c) marginal (d) conditional (e) joint
a) marginal
b) joint
c) dependent
d) independent
e) conditional
Placebo | Drug | Sum | |
Cold | 36 | 87 | 123 |
No Cold | 224 | 333 | 557 |
Sum | 260 | 420 | 680 |
The probabilities are
Placebo | Drug | Sum | |
Cold | 36/680 = 0.052 | 87/680 = 0.127 | 123/680 = 0.181 |
No Cold | 224/680 = 0.329 | 333/680 = 0.489 | 557/680 = 0.819 |
Sum | 260/680 = 0.382 | 420/680 = 0.618 | 680 |
The probabilities with sum are called as Marginal Probabilities which are maked in blue and the probabilties for individuals like cold, no cold, placebo, drug are called joint probabilities which are marked in orange
Question
The probability that a patient has No Cold is 557/680
= 819 = 0.82 rounded to two decimals
This is a marginal probability
So Answer is C
Question (15)
The probability that a patient istaking placebo and has No Cold is 224/680
= 0.329 = 0.33 rounded to two decimals
This is a joint probability
So Answer is B
Question (16)
The probability that a patient is taking Placebo or has No Cold
Consider Placebo be Pl and No Cold be NC
Here we need P(Pl NC) = P(Pl) + P(NC) - P(Pl NC) which is the correct formula
P(PI) = 0.382 , P(NC) = 0.819, P(Pl NC) = 0.329
P(Pl NC) = 0.382 + 0.819 - 0.329
= 0.872 = 0.87 rounded to two decimals
I havr already given the formula. Could you please specify the format given in the answers for the formaul so i can explain you more
Question (17)
Conditional probability P(No Cold | taking the drug), P(No Cold | taking Placebo), P(taking drug | No Cold)
P(No Cold | taking the drug) = P(No Cold taking the drug) / P (taking the drug)
The formual for P(A | B ) = P(AB) / P(B)
P(No Cold | taking the drug = 0.489 / 0.618
= 0.791 = 0.79 rounded to two decimals
P(No Cold | taking placebo) = P(No Cold taking placebo) / P (placebo)
= 0.329 / 0.382
= 0.861 = 0.86 rounded to two decimals
P(taking drug | No Cold) = P(taking drug No cold) / P (No cold)
= 0.489 / 0.819
= 0.597 = 0.6 rounded to two decimals
I havr already given the formula. Could you please specify the format given in the answers for the formaul so i can explain you more
Question (18)
For two variables A,B to be independent P(AB) shpuld be equal to P(A) * P(B)
If we take one raw variable as Cold and one column variable as Drug
P(Cold Drug ) = 0.127
P(Cold) = 0.181
P(Drug) = 0.618
P(Cold) * P(Drug) = 0.181 * 0.618
= 0.112
Since P(Cold Drug ) is not equal to P(Cold) * P(drug) they are not independent so they should be dependent.
So the Answer is C
The Probability of Drug changes on whether they have cold or not, so they are dependent
Likewise all other row and column variables are dependent on each other