Question

In: Chemistry

The low-frequency relative permittivity of water is 88.00 at 0°C. At the same temperature, the index...

The low-frequency relative permittivity of water is 88.00 at 0°C. At the same temperature, the index of refraction (at 589.3 nm) is roughly 1.33.

a.Which mechanisms contribute to the refractive index and to the relative permittivity?

b.Why is the refractive index so much smaller than the relative permittivity at low frequencies?

Solutions

Expert Solution

a) Relation between the index of refraction to the relative permittivity (dielectric constant/function) is known that n = √ ϵ r n=ϵr for optical frequencies (i.e. μ r = 1).

n=ϵr−−√n=ϵr works. It is just that the dielectric “constant” isn’t actually a constant. For under 1kHz, water’s dielectric “constant” is around 86. But for visible light (600THz, 500nm), water has a dielectric “constant” of 1.77, which gives you the refractive index of 1.33.We know that the relative permittivity of water as 80.4 i.e. ϵ r = 80.4 ϵr=80.4 but we also know that the index of refraction of water is 1.33. so it should be n = √ ϵ r = √ 80.4 = 8.9666
We want to use the relative permittivity in an equation to calculate the electrostatic approximation of the scattering/absorption efficiencies of small spherical particles. should i be solving for relative permittivity from the index of refraction? i.e. n 2 = ( √ ϵ r ) 2 ⇒ ϵ r = 1.33 2 = 1.7689
Permittivity is a function of wavelength (frequency). 80.4 value is valid for microwave diapason, not for optical one. For optical frequencies you should calculate permittivity from refractive index, i.e. ϵ r = n 2

b) The reason why the dielectric “constant” isn’t constant is it is a product of the polarization of the material. Polarization is the ability of a material to polarize. Think of a magnet that gets stronger, except instead of a magnet, we’re talking about electrical forces. The more the polarization mechanisms, the higher the dielectric “constant.” There are four major polarization mechanisms. They are electronic polarization, ionic polarization, orientation polarization, and interface polarization.

Each of the polarization mechanisms only works up until a certain frequency, so at higher frequencies, less polarization mechanisms are active in any material. That is what happens in water at light’s frequency. Water losses its orientation polarization mechanism with light. Below is a chart that demonstrates how the polarizability and thereby the dielectric “constant” changes with frequency.

If you are happy with my answer, Please press "like".

Thank You


Related Solutions

In a low temperature drying system, air at 60°C and 10% Relative humidity passes over a...
In a low temperature drying system, air at 60°C and 10% Relative humidity passes over a bed of diced carrots at 20 kg-dry air/sec. The rate of water removal from the carrots Is measured by difference in total weight over time and found to be approximately .16 kg-water/sec. In the system described above, calculate the temperature and relative humidity of the air exiting the drying system.
When the air temperature is below 0 ?C, the water at the surface of a lake...
When the air temperature is below 0 ?C, the water at the surface of a lake freezes to form a sheet of ice. If the upper surface of an ice sheet 24.64cm thick is at -10.58?C and the bottom surface is at 0 ?C, calculate the time it will take to add 2.41mm to the thickness of this sheet.
Table 1: Temperature of Frozen Water Over Time Time (min.) Temperature (°C) Observation 0 -12 Water...
Table 1: Temperature of Frozen Water Over Time Time (min.) Temperature (°C) Observation 0 -12 Water is frozen 5 0 Water is frozen 10 1 Ice is attached to thermometer but unstuck from test tube 15 14 There is a pool of water in the bottom of the test tube 20 2 The pool of water is flightly bigger, ice chunk is getting smaller 25 4 The ice chunk is over halfway melted 30 5 The Ice chunk is over...
Derive C-V characteristics for n-type MOS at high frequency and low frequency
Derive C-V characteristics for n-type MOS at high frequency and low frequency
Derive C-V characteristics for n-type MOS at high frequency and low frequency
Derive C-V characteristics for n-type MOS at high frequency and low frequency
It is well known that water freezes at 0°C at atmospheric pressure. The mixture of liquid water and ice at 0°C is said to be
It is well known that water freezes at 0°C at atmospheric pressure. The mixture of liquid water and ice at 0°C is said to be at stable equilibrium since it cannot undergo any changes when it is isolated from its surroundings. However, when water is free of impurities and the inner surfaces of the container are smooth, the temperature of water can be lowered to 22°C or even lower without any formation of ice at atmospheric pressure. But at that...
Construct a relative frequency distribution of your data. Remember each class should have the same width,...
Construct a relative frequency distribution of your data. Remember each class should have the same width, for example, classes of 0 to 5, 6 to 10, 11 to 15, etc. In 3 tabs: classes frequency relative frequency Data: The researcher asks 25 students, "On average, how many hours daily a college student spends on social networks?" Respondent   Hours of S.N. 1 1h40m 2 2h30m 3 2h30m 4 2h30m 5 2h10m 6 2h 7 2h 8 3h 9 2h20m 10 2h20m...
Day High temperature, C Low temperature, C 1 30 25 2 32 26 3 34 23...
Day High temperature, C Low temperature, C 1 30 25 2 32 26 3 34 23 4 29 20 5 31 19 6 30 21 7 25 18 The high and low temperatures of each day in Wichita KS are given in Table. (1 pt) (a) Plot the high temperature for 7 days as a function of day, i.e., high temperature on y-axis, and day # on x-axis. Use the red, empty square as a marker with the solid line....
A metal rod at 38°C is placed in a room at a constant temperature of 0°C....
A metal rod at 38°C is placed in a room at a constant temperature of 0°C. (a) If after 20 minutes the temperature of the rod is 20°C, find the temperature function T(t) that models the temperature T of the rod at time t. Assume Newton's Law of Cooling. Note: You must state the differential equation that models this situation and include how to solve this DE as part of your solution. (b)Determine the time it will take for the...
Water is cooled to 32K, and it appears to be on the solid phase on the phase changing diagram as the temperature is low.
Water is cooled to 32K, and it appears to be on the solid phase on the phase changing diagram as the temperature is low. We compress the ice to a temperature of 340-350K (around 30ATM on the pressure dial).a. Where is the red dot now located in the phase changing diagram? Would it be on the line between liquid and gas phases?b. What does that position on them phase change diagram say about pressure and temperature?c. What happens to the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT