Question

SOLUTION CALCULATION

YOU WISH TO PREPARE 50.0mL of 2.30 X 10^ -2 of XANAX. DESCRIBE HOW TO PREPARE THIS SOLUTION FOR THE PURE DRUG AND DEIONIZED WATER. ANALYTICAL BALANCES AND VOLUMETRIC FLASKS ARE AVAILABLE TO YOU. USE COMPLETE SENTENCES IN YOUR DESCRIPTION OF THE SOLUTION PREPARATION PROCESS SHOW ANY REQUIRED CALCULATIONS YOU NEED TO MAKE.

Answer 1

Ans. The unit of concertation of solution is NOT mentioned in the question.

It’s assumed that the unit of concertation is “Molarity, M”.

Molarity is defined as moles of solute per liter of solution.

# Given,          [Xanax] = 2.30 x 10^-2 M

            Volume of solution = 50.0 mL = 0.050 L

Now,

            Required moles of Xanax = Molarity x Volume of solution in liters

                                                = (2.30 x 10^-2 M) x 0.050 L

                                                = 1.150 x 10^-3 mol

            Required mass of Xanax = Required moles x Molar mass

                                                = 1.150 x 10^-3 mol x (308.76 g/mol)

                                                = 0.355074 g

                                                = 0.3551 g

# Steps of Preparation:

I. Accurately weigh and transfer 0.3551 g Xanax to small quantity of deionized water taken in a clan 50.0 mL class A volumetric flask.

II. Gradually add deionized water in small volumes with constant swirling and mixing top dissolve all the drug crystals. Note the volume till this step shall not exceed 2/3 of the marked volume capacity of the flask.   

III. Make the final volume upto the mark with deionized water. Mix well to get a homogenous solution.

It is the desired solution, 2.30 x 10^-2 M of Xanax.