In: Physics
When the air temperature is below 0 ?C, the water at the surface of a lake freezes to form a sheet of ice.
If the upper surface of an ice sheet 24.64cm thick is at -10.58?C and the bottom surface is at 0 ?C, calculate the time it will take to add 2.41mm to the thickness of this sheet.
Consider a section of ice that has Area = A
At time t, let the thickness be h.
Short time interval t to t + dt.
Let the thickness that freezes in this time be dh.
The mass of the section that freezes in the time interval dt is dm = pdv = pAdh.
The heat that must be conducted away from this mass of water to freeze it is
dq = dmLr = (pALr)dh.
H=dq/dt = kA(T/h)
So the heat dq conducted in time dt troughout the thickness h that is already there is
dq=kA(Tu-Tc/h)dt.
pALrdh=kA(Tu-Tc/h)dt.
hdh=(k(Tu-Tc)/pLr)dt.
Integrate from t=0 to time t.
At t=0 , h=0
h = squareroot of(2k(Tu-Tc)/pLr)*squareroot of t
The thickness after t is proportional to squareroot of t.
t = h^2pLr/2k(Tu-Tc)
= [(0.0024m)^2(920 kg/m3)(334*10^3J/kg)]/2(1.6w/mk)(0.c-(-10.58))
t = 0.015 hr.or approximately 53 s.