##### Question

In: Mechanical Engineering

# a-Calculate conventional yield effort at 0.2% (0.002 in./in.) b- Tensile strength. c- The modulus of elasticity....

a-Calculate conventional yield effort at 0.2% (0.002 in./in.)

b- Tensile strength.
c- The modulus of elasticity.
d- Elongation
e- The reduction in area.
f- The engineering effort to fracture
g- The real stress to fracture
h- The modulus of resilience

Magnesium

 Load (N) Calibrated length (mm) 0 30.00000 5000 30.02960 10000 30.0592 15000 30.0888 20000 30.1500 25000 30.51 26500 30.9 27000 31.5 26500 32.1
 25000 32.79

- Initial diameter of the test tube: 12 mm
- Initial calibrated length: 30 mm
- Calibrated length after fracture: 32.61 mm
- Diameter after fracture. 11.74 mm

## Solutions

##### Expert Solution

Solution:

a) Yield strength at 0.002

From the following stress-strain curve, at 0.002 strain the yield strength is approx 188 MPa

b) Tensile strength

From the stress-strain curve, the tensile strength is defined as the maximum stress. The approx tensile strength is 238.85 MPa

c) The modulus of elasticity

Therefore, the modulus of elasticity is 45132.65 MPa

d) % Elongation

Therefore, the approx % of elongation is 8.7%

e) The reduction in area

Therefore, the apporx reduction in area is 4.28%

f) The engineering effort to fracture

The stress at fracture is approx 221.16 MPa

g) The real stress to fracture

The relationship between true stress and engg.stress is

Therefore, the real stress to fracture is 241.72 MPa

h) The modulus of resilience

The formula used to find the modulus of resilience is

Therefore, the modulus of resilience is 0.392

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