In: Statistics and Probability
The following data was collected to explore how a student's age and GPA affect the number of parking tickets they receive in a given year. The dependent variable is the number of parking tickets, the first independent variable (x1) is the student's age, and the second independent variable (x2) is the student's GPA.
Age | GPA | Number of Tickets |
---|---|---|
23 | 3 | 7 |
22 | 3 | 6 |
21 | 2 | 5 |
21 | 2 | 4 |
20 | 2 | 2 |
19 | 2 | 2 |
18 | 2 | 2 |
18 | 2 | 2 |
18 | 2 | 0 |
Step 1 of 2 :
Find the p-value for the regression equation that fits the given data. Round your answer to four decimal places.
Step 2 of 2 :
Determine if a statistically significant linear relationship exists between the independent and dependent variables at the 0.050.05 level of significance. If the relationship is statistically significant, identify the multiple regression equation that best fits the data, rounding the answers to three decimal places. Otherwise, indicate that there is not enough evidence to show that the relationship is statistically significant
How to enter your answer
Selecting a checkbox will replace the entered answer value(s) with the checkbox value. If the checkbox is not selected, the entered answer is used.
y^= +____ x1 +___ x2 or There is not enough evidence.
Submit Answer
using excel data analysis tol for regression
excel>menu>data>data analyisis>regression>enter required labels>ok
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.940487 | |||||||
R Square | 0.884517 | |||||||
Adjusted R Square | 0.846022 | |||||||
Standard Error | 0.899101 | |||||||
Observations | 9 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 2 | 37.1497 | 18.57485 | 22.97778 | 0.00154 | |||
Residual | 6 | 4.850299 | 0.808383 | |||||
Total | 8 | 42 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | -18.2635 | 3.722726 | -4.90594 | 0.002695 | -27.3727 | -9.15429 | -27.3727 | -9.15429 |
Age | 0.976048 | 0.260324 | 3.749356 | 0.009517 | 0.339058 | 1.613038 | 0.339058 | 1.613038 |
GPA | 0.934132 | 1.104462 | 0.84578 | 0.430108 | -1.76839 | 3.636652 | -1.76839 | 3.636652 |
1)
p-value = 0.0015
2)
since, p-value = 0.0015 <α=0.05, so
there is enough evidence to show that the relationship is statistically significant
Y^ = -18.2635 + 0.9760*X1 + 0.9341*X2