In: Statistics and Probability
The following data are from a repeated-measures study examining the effect of a treatment by measuring a group of n=5 participants before and after they receive the treatment.
A.) calculate the difference scores and MD
B.) compute SS, sample variance, and estimated standard error.
C.) is there a significant treatment effect? Use Alpha=0.05
Participant Before Treatment After Treatment
A 8 7
B 7 5
C 6 6
D 7 6
E 9 7
Participant Before After difference
A 8 7 1
B 7 5 2
C 6 6 0
D 7 6 1
E 9 7 2
MD = (1 + 2 + 0 + 1 + 2)/5 = 1.2
b) SS = (1 - 1.2)^2 + (2 - 1.2)^2 + (0 - 1.2)^2 + (1 - 1.2)^2 + (2 - 1.2)^2 = 2.8
Sample variance(sd2) = SS/(n - 1) = 2.8/4 = 0.7
c)
The test statistic is
df = 5 - 1 = 4
At alpha = 0.05, the critical values are +/- t0.025,4 = +/- 2.777
Since the test statistic value is greater than the upper critical value(3.21 > 2.777), so we should reject the null hypothesis.
At 0.05 significance level, there is sufficient evidence to conclude that there is a significant treatment effect .
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