a)Consider an aqueous solution of ammonium chloride, NH4Cl.
Neglecting the autoprotolysis of water, calculate the pH of NH4Cl
for formal concentration of 0.10M.
b)Use the systematic treatment of equilibrium to derive an
equation for an aqueous solution of NH4Cl that contains [H+], F, Ka
and Kw. Do not neglect the autoprotolysis of water in this
case.
1. In one step, ammonium chloride (NH4Cl) was added to lower the
blood pH. The ammonium ion is what acts as the acid. The chloride
ion does not have any acid/base properties.
a. Why is the ammonium ion used as the acid source instead of
HCl?
b. Why is NH4Cl used instead of some other ammonium compound
(such as NH4NO3 or NH4I)?
Calculate the OH- concentration and pH of a 3.7×10-3M aqueous
solution of sodium cyanide, NaCN. Finally, calculate the CN-
concentration. Ka (HCN) = 4.9×10-10.
What is the pH of a 0.055 M solution of sodium cyanide
(NaCN)? The Ka value for hydrocyanic acid (HCN)
is 6.2 x 10-10.
Select one:
a. 10.97
b. 10.08
c. 8.77
d. 3.03
e. 5.23
Ammonia rapidly reacts with hydrogen chloride, making ammonium
chloride. Calculate the number of grams of excess reactant when
6.16 g of NH3 reacts with 4.46 g of HCl