Question
In: Chemistry
Calculate the ph after mixing 100 ml of .075 M ammonium chloride with 76 ml of...
Calculate the ph after mixing 100 ml of .075 M ammonium chloride with 76 ml of .1 M LiOH
Solutions
Expert Solution
NH4Cl millimoles = 100 x 0.075 = 7.5
LiOH millimoles = 76 x 0.1 = 7.6
NH4Cl + LiOH ----------------------------> NH4OH + LiCl
7.5 7.6 0 0 ----------------> initial
0 0.1 7.5 7.5
LiOH is strong base . so pH decided by LiOH
LiOH concentration = millimoles / total volume
= 0.1 / 100+ 76
= 5.68 x 10^-4 M
pOH = -log [OH-] = -log (5.68 x 10^-4) = 3.25
pH +pOH =14
pH = 10.75
queen_honey_blossom answered 1 year agoRelated Solutions
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