Calculate the ph after mixing 100 ml of .075 M ammonium chloride with 76 ml of...

Calculate the ph after mixing 100 ml of .075 M ammonium chloride with 76 ml of .1 M LiOH

Expert Solution

NH4Cl millimoles = 100 x 0.075 = 7.5

LiOH millimoles = 76 x 0.1 = 7.6

NH4Cl + LiOH ----------------------------> NH4OH + LiCl

7.5 7.6 0 0 ----------------> initial

0 0.1 7.5 7.5

LiOH is strong base . so pH decided by LiOH

LiOH concentration = millimoles / total volume

= 0.1 / 100+ 76

= 5.68 x 10^-4 M

pOH = -log [OH-] = -log (5.68 x 10^-4) = 3.25

pH +pOH =14

pH = 10.75

queen_honey_blossom answered 8 months ago

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Calculate the ph after mixing 100 ml of .075 M ammonium chloride with 76 ml of...

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