Question

Standardized stock price indicators in three different countries over a week are listed below. An analyst is interested in knowing if the stock markets of these different countries are dependent on one another. The data set and a partial ANOVA table for this study are provided below. I II III 890 900 905 899 900 900 900 887 896 905 906 928 871 893 899 910 900 934 Source of variation SS DF MS F Treatment 748 2 374 ??? Error 2526 ??? ??? Total 3274 ???

Compute the MSE and the F statistic

		MSE = 374. F = 2.22
		MSE = 168.4. F = 2.22
		MSE = 2.22. F = 15
		MSE = 2,526. F = 2.22
		None of the above Suppose the p-value for the test is 0.143. At the 0.05 level of significance, how do you conclude? Do not reject H0. There is no evidence that the means are significantly different Do not reject H0. Evidence exists that the means are significantly different Reject H0. There is no evidence that the means are different Reject H0. P-value is greater than alpha None Calculate the Tukey Criterion (T) for use in a Tukey pairwise comparisons test. Use alpha of 0.05. T = 3.67 T = 19.05 T = 19.44 None of the above of the above statements is correct Which of the pairs of sample means are statistically significant? Sample means for Groups 1 and 2 Sample means for Groups 1 and 3 Sample means for Groups 2 and 3 None is significant

Answer 1

Source	SS	df	MS	F
treatment	748	2	374	2.22
error	2526	15	168.4
total	3274	17

1)

MSE = 168.4. F = 2.22

2)

Do not reject H0. There is no evidence that the means are significantly different

3)

pooled standard deviation                                                                             =Sp =√MSE      =						12.976
critical value of q with 0.05 level and at k=3 and N-k=15 degree of freedom=						3.673
Tukey's (HSD) for group i and j =                  (q/√2)*(sp*√(1/ni+1/nj)         =						19.44

4)

None is significant