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In: Chemistry

The analyst found the molarity of the standardized NaOH solution to be 0.1028 mol/L. Three aliquots...

The analyst found the molarity of the standardized NaOH solution to be 0.1028 mol/L. Three aliquots of the unknown sample having weights of 0.8150 g, 0.9289 g, and 0.8676 g were titrated with the NaOH solution requiring 18.98 mL, 22.78 mL, and 23.04 mL, respectively. From these data, determine the average percent KHP in the unknown sample.

Expert Solution

Remember that at end point:

Where: M.W = molecular weight; N=normality; V=volume; =number of hydrogens or hydroxide ions.

Also, KHP is a monoprotic acid, so =1

For test 1:

For test 2:

For test 3:

Then, the average percent of KHP is:

I hope it was clear.

queen_honey_blossom answered 2 years ago

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