A poll is given, showing 75% are in favor of a new building project. If 138 people are chosen at random, answer the following. What is the probability that exactly 103 of them are in favor of a new building project? What is the probability that less than 103 of them are in favor of a new building project? What is the probability that more than 103 of them are in favor of a new building project? What is the probability that exactly 110 of them are in favor of a new building project? What is the probability that at least 110 of them are in favor of a new building project?
In: Math
Components of a certain type are shipped to a supplier in batches of ten. Suppose that 48% of all such batches contain no defective components, 29% contain one defective component, and 23% contain two defective components. Two components from a batch are randomly selected and tested. What are the probabilities associated with 0, 1, and 2 defective components being in the batch under each of the following conditions? (Round your answers to four decimal places.)
(a) Neither tested component is defective.
no defective components: one defective component:
|
In: Math
Table 2
INDIANA |
ALASKA |
||||
Age in years |
Standard population US 1992 (a) |
Age-specific Death rate Per 1000 (b) |
Expected Deaths (c) |
Age-specific Death rate Per 1000 (d) |
Expected Deaths (e) |
<15 |
57421054 |
0.92 |
0.96 |
||
15-44 |
118956356 |
1.31 |
1.85 |
||
45-64 |
50888153 |
7.28 |
6.19 |
||
>65 |
33158009 |
52.10 |
41.69 |
||
Total |
260423572 |
XXXXXXX |
XXXXXXX |
Column b will be taken directly from Table 1. Calculate the age-adjusted rates: Add the expected deaths for each state, i.e. columns (c) and (e). Divide the total expected deaths in each state by the total standard population of the US.
Calculate the age-adjusted rates: Add the expected deaths for each state, i.e. columns (c) and (e). Divide the total expected deaths in each state by the total standard population of the US.
7. Calculate the age-adjusted death rate per 1000 for each state: (5 points)
In: Math
please answer the question using Excel with formula please explain how the answer came
5798744651195376549552374814657837175920
In: Math
sales | sqft | adv_cost | inventory | distance | district_size | storecount |
231 | 1.47 | 7.62 | 897 | 10.9 | 79.48 | 40 |
232 | 1.53 | 9.57 | 892 | 9.4 | 51.154 | 12 |
156 | 1.68 | 8.37 | 542 | 7.9 | 60.358 | 41 |
157 | 1.355 | 6.73 | 552 | 6.8 | 55.561 | 68 |
10 | 1.33 | 1.66 | 242 | 3.5 | 89.624 | 14 |
10 | 1.33 | 1.17 | 235 | 3.6 | 86.898 | 62 |
519 | 1.89 | 12.96 | 3670 | 18.5 | 108.857 | 56 |
520 | 1.885 | 12.02 | 3657 | 19.1 | 100.685 | 75 |
437 | 1.7 | 12.29 | 3345 | 17.4 | 90.138 | 59 |
487 | 1.86 | 12.5 | 3322 | 16.5 | 111.284 | 22 |
299 | 1.4 | 9.86 | 1784 | 11.5 | 75.606 | 26 |
195 | 1.63 | 7.22 | 1230 | 9.8 | 64.245 | 27 |
20 | 1.24 | 5.23 | 483 | 2.4 | 55.929 | 11 |
68 | 1.51 | 3.93 | 114 | 4.5 | 73.187 | 33 |
428 | 1.78 | 11.04 | 2829 | 16.4 | 101.192 | 51 |
429 | 1.725 | 9.43 | 3410 | 15.7 | 80.694 | 16 |
464 | 1.72 | 12.19 | 2873 | 15.8 | 105.254 | 84 |
15 | 1.2 | 1.17 | 289 | 3.2 | 80.937 | 31 |
65 | 1.47 | 6.56 | 292 | 3.9 | 80.187 | 97 |
66 | 1.51 | 5.55 | 312 | 3.8 | 85.897 | 66 |
98 | 1.24 | 5.79 | 235 | 6.4 | 90.219 | 75 |
338 | 1.65 | 3.34 | 1160 | 12.1 | 121.988 | 84 |
249 | 1.513 | 2.23 | 1184 | 9.7 | 115.277 | 12 |
161 | 1.4 | 6.95 | 399 | 7.9 | 50.188 | 14 |
467 | 1.46 | 13.17 | 2062 | 16.1 | 101.211 | 89 |
398 | 1.84 | 11.68 | 2103 | 15.9 | 95.406 | 49 |
497 | 1.68 | 12.11 | 2743 | 18 | 80.195 | 14 |
528 | 1.94 | 10.98 | 3779 | 18 | 110.025 | 58 |
529 | 1.765 | 11.11 | 3916 | 18.9 | 103.26 | 52 |
99 | 1.31 | 4.35 | 782 | 4.8 | 111.732 | 52 |
100 | 1.525 | 3.79 | 804 | 4.7 | 99.7 | 41 |
1 | 1.45 | 4.68 | 1116 | 3.4 | 85.882 | 50 |
347 | 1.65 | 10.08 | 2223 | 13.4 | 94.181 | 49 |
348 | 1.811 | 7.87 | 2180 | 12.1 | 95.242 | 50 |
341 | 1.64 | 10.34 | 1494 | 14.3 | 70.693 | 28 |
557 | 1.66 | 13.55 | 3522 | 18.5 | 94.329 | 43 |
508 | 1.698 | 11.53 | 3521 | 16.7 | 99.917 | 50 |
In the “HomeSales” dataset, the response variable, sales, depends on six potential predictor variables, sq_ft, adv_cost, inventory, distance, district_size, and storecount. Fit four simple linear regression (SLR) models corresponding to the four predictors, sq_ft, adv_cost, inventory, and distance. Then, for each model, create a normal probability plot and a histogram for the residuals, together with the two residual scatterplots: residuals vs. fitted values and residuals vs. observation order.
What do the residual plots for the model with sq_ft as the predictor indicate about the validity of this regression model and assumptions made about the errors?
What do the residual plots for the model with adv_cost as the predictor indicate about the validity of this regression model and assumptions made about the errors?
What do the residual plots for the model with inventory as the predictor indicate about the validity of this regression model and assumptions made about the errors?
What do the residual plots for the model with distance as the predictor indicate about the validity of this regression model and assumptions made about the errors?
One objective of this analysis is to obtain an appropriate simple linear regression model that can be used to estimate the average sales based on a single predictor. State your “best” choice based on your conclusions in parts (a)–(d).
Complete the table below, using the regression analysis results of the four simple linear regression models considered in parts (a)–(d). Based on the table entries, would you change your “best” choice from part (e).
Model predictor |
S |
R2 |
t-stat |
sqft |
110.75 |
66.44% |
8.32 |
adv_cost |
|||
inventory |
|||
distance |
A model including the predictor variable adv_cost is of specific interest. Obtain appropriate residual plots and determine if adding either district_size or storecount as an additional predictor to the SLR model with predictor adv_cost is likely to improve its fit.
In: Math
Problem 16-05 (Algorithmic)
A major traffic problem in the Greater Cincinnati area involves traffic attempting to cross the Ohio River from Cincinnati to Kentucky using Interstate 75. Let us assume that the probability of no traffic delay in one period, given no traffic delay in the preceding period, is 0.8 and that the probability of finding a traffic delay in one period, given a delay in the preceding period, is 0.65. Traffic is classified as having either a delay or a no-delay state, and the period considered is 30 minutes.
In: Math
Number of defective monitors manufactured in day shift and afternoon shift is to be compared. A sample of the production from six day shifts and eight afternoon shifts revealed the following number of defects.
Day 4 5 8 6 7 9
Afternoon 9 8 10 7 6 14 11 5
Is there a difference in the mean number of defects per shift? Choose an appropriate significance level.
(a) State the null hypothesis and the alternative hypothesis.
(b) What is the decision rule?
(c) What is the value of the test statistic?
(d) What is your decision regarding the null hypothesis?
(e) What is the p-value? (f ) Interpret the result.
(g) What assumptions are necessary for this test?
(Typed answer preferred)
In: Math
Statistics and Graphical Displays
Valencia Orange Price Comparison
You have been hired as a consultant to determine who ABC Grocery Store should be ordering Valencia Oranges from.
To: Statistician
From: ABC Grocery Store
Please advise us on which company to use as our orange distributor. Three highly recommended distributors have provided us with statistical data on the weekly prices for one load of Valencia oranges per week for a ten-week period last year. Prices fluctuate according to availability, and we would like to use the company with the lowest overall price and the least amount of fluctuation. We would like your written report showing your results and a detailed recommendation as to which company we should choose.
Here are the prices, listed as price in dollars per crate:
Week |
The Fruit Guys |
Sunny Oranges |
Tree Groves |
1 |
350 |
345 |
345 |
2 |
350 |
295 |
340 |
3 |
310 |
325 |
310 |
4 |
330 |
315 |
290 |
5 |
340 |
290 |
305 |
6 |
290 |
305 |
290 |
7 |
305 |
300 |
320 |
8 |
315 |
315 |
320 |
9 |
325 |
340 |
300 |
10 |
355 |
350 |
359 |
You must type in and analyze the data for each company.
Helpful directions:
The Fruit Guys | Sunny Oranges | Tree Groves | |
Mean | 327 | 318 | 317.9 |
Median | 327.5 | 315 | 315 |
Mode | 350 | 315 | 290,320 |
Standard Deviation | 20.761 | 20.273 | 22.421 |
Range | 65 | 60 | 69 |
Frequency | 3270 | 3180 | 3179 |
Relative Frequency | 355 | 350 | 359 |
In: Math
A personnel director claims that the distribution of the reasons withers leave their job is different from the distribution: 41% limited advancement; 25% lack of recognition; 15% low salary/benefits; unhappy with management 10%; 9% bored. You randomly select 200 workers who recently left their jobs and record each worker’s reasons for doing so. The table below show the results. At the 0.01 level of significance, test the personnel director’s claim.
Survey Results |
|
Response |
Frequency |
Limited advancement |
78 |
Lack of recognition |
52 |
Low salary/benefits |
30 |
Unhappy with management |
25 |
Bored |
15 |
Expected Frequencies for each?
In: Math
A study might compare the rates of microbiologic cure of three different antibiotics used for urinary tract infection, as shown in the following table:
Antibiotics 1 |
Antibiotics 2 |
Antibiotics 3 |
Total |
|
Cure |
49 |
112 |
26 |
187 |
Not cure |
12 |
37 |
8 |
57 |
Total |
61 |
149 |
34 |
244 |
Is there is a relationship between which antibiotic the patient took and achieving microbiologic cure?
In: Math
For the problems 1 -6
Consider the data set
16, 26, 31, 32, 32, 32, 42, 47, 47, 47, 50, 50 (already put in
increasing order)
Compute the following:
1/ The mode:
A/ 47 B/ 32 C/ Bimodal D/ 42
2/ The median:
A/ 42 B/ 37 C/ 32 D/ 47
3/ The mean:
A/ 37.7 B/ 37 C/ 36 D/ 36.2
4/ The standard deviation:
A/ 10.5 B/ 12 C/ 14 D/ 11
5/ The mid-range:
A./ 17 B/ 20.5
C/ 33
D/ 34
6/ If x = 42 , the standard deviation s = 12 and the
mean = 67, then the z-score ( the standard score) of x is
A./ 2.28 B/ - 1.00
C/ 3.52 D/
-2.08
7/ In the set of data : 2, 3, 35, 5, 8, 9,10,
10,12,14,16, is the value 35 outlier?
A/ No, upper limit for outlier is 27.5
B/ Yes, upper limit for outlier is 27.5
C/ No, upper limit for outlier is 24.5
D/ Yes, upper limit for outlier is 32.1
For the problems 8 -13: Consider the set of 15 data ( in increasing order )
10, 15, 19, 20, 21, 21, 29, 29, 30, 30, 33, 39, 40, 50, 50.
( It is better to enter this data set into a calculator to find the needed values to answering the following questions )
8/ Find ( the value x which separates the bottom 30th percentile )
A./ 70 B/ 21 C/ 29.5 D/ 53
9/ Find the percentile ( kth percentile ) of the value x = 30.
A/ 53 percentile B/ 82 percentile C/ 38 percentile D/ 60 percentile
10/ The third quartile () is:
A./ 39 B/ 17 C/ 40 D/ 18
11/ The inter-quartile range ( IQR) is:
A./ 17 B/ 21 C/ 19 D/ 59
12/ The sample variance is approximate to ( round to whole number )
A./ 11 B/ 148
C/ 12 D/
142
13/ Approximate the value of x if its z-score is 0.83 ( Use the formula )
A./ 35 B/ 39
C/ 19
D/ 25
14/ For the data set 8, 6, 29, 3, 9, 23, 15, 18, 5, 3,
22, 27, 4, 2 and 22 the midrange is
A./ 16 B/ 11
C/ 15
D/ 18
15/ By the Empirical Rule, in a city of 62,000 people, the number of people below the mean by more than 1 standard deviation is:
A./ 41,160 B/ 9, 920
C/ 21,080 D/
6,200
Questions 16-18 : Use the distribution in the form of the stem-leaf
plot
Stem Leaves
1478
01237888
189
16/ The mid-point of the third class is
A./ 32 B/ 36 C/ 34.5 D/ 35
17/ The median is
A./ 24 B/
23 C/ 25
D/ 5
18/ The relative frequency for the third class is:
A./ 20% B/ 50% C/ 66% D/ 40%
19/ The heights of a group of professional basketball players are summarized in the frequency distribution below. Find the mean height from this frequency table.
Height s (
in) Frequency
4
6
8
79-81 2
A./ 75.2 in B/ 76.8 in
C/ 74.0 in D/
77.5 in
20/ The temperatures ( in ºF ) in a room is recorded at
the top of hours are
67, 68, 70 , 5, 77, 77, 78, 80, 78, 79, 74, 74.
Choose best answer:
a/ It is a typo
b/ highest temperature is probably 95
c/ 5 is not an outlier
d/ 5 is an outlier
21/ The variance of 6 washing machines with prices: $
800, $784, $ 1,235, $860, $1,036 and $770 is
A/ 196.4 B/ 34,295.3
C/ 26,002.7 D/
185.2
22/ The coefficient of variation ( round to closest %)
for the set of data :
1, 3, 3, 5, 5, 6, 7, 8, 9 ,12, 15, 24 is
A 74% B/ 67%
C/ 24% D/ 78
%
23/ Human body temperatures have the mean of 98.2º
and a standard deviation of 0.6º.
Amy’s temperature can be described by z = 0.9. What is
her temperature?
A/ 98.2º B/ 97.8º C/ 98.7º D/ 99.3º
24/ The upper bound for the outlier for the data
set
-11, 14, 22, 22, 22, 23, 31, 31, 42, 44, 44, 75 is
A/ 74.5 B/
75 C/
84 D/ 68
25/ The box-plot of a data with 5- point summary 2, 6,
8, 11, 18
A/is positive skewed.
B/ is negative skewed.
C/ is symmetric D/
perfect skewed
In: Math
Let X ~ N(196; 19). Find:
(a) P(X </= 223)
(b) P(143 < X < 206)
(c) P(|X-196|> 30)
In: Math
Background
The 2016 US Presidential Election brought considerable attention to the phenomenon of “fake news”: entirely fabricated and often partisan content that is presented as factual. Researchers evaluated one mechanism that may contribute to the believability of fake news: fluency via prior exposure. Using an actual fake news headline presented as it was seen on Facebook (Kid Rock launches campaign to run for U.S. Senate in 2018), the researchers hypothesized that previous exposure to the fake news story would increase perceptions of accuracy. Subjects were pre-screened to determine in which of 3 groups they belonged: 1) no previous exposure to the fake news story, 2) previous exposure to the fake news story and had not heard that the story was, in fact, fake, or 3) previous exposure to the fake news story but had heard that the story was, in fact, fake. They recorded perception of the accuracy of the news story (ranging from 1 (definitely false) to 6 (definitely true)).
Please complete all empty boxes in the tables below.
Data
No exposure (Group A) |
Previous exposure, not informed it was fake (Group B) |
Previous exposure, informed it was fake (Group C) |
|
1 |
3 |
6 |
|
1 |
6 |
6 |
|
2 |
6 |
6 |
|
4 |
4 |
5 |
|
1 |
5 |
5 |
|
4 |
4 |
4 |
|
3 |
5 |
3 |
|
2 |
6 |
4 |
|
1 |
6 |
6 |
|
6 |
3 |
3 |
|
5 |
3 |
6 |
|
Mean |
|||
St. Dev |
1.79 |
1.29 |
1.22 |
n |
|||
N |
One-way ANOVA (please show your work!)
Source of variability |
df |
SS |
MS |
F |
h2 |
|
Between-groups |
31.09 |
|||||
Within-groups (error) |
63.64 |
|||||
Total |
94.73 |
|||||
Critical F-value (obtain from F table) |
||||||
Is the ANOVA significant? Y or N |
||||||
Post-hoc results using the Tukey test
Comparison |
p-value |
Significant? Y or N |
Group A versus Group B |
.0095 |
|
Group A versus Group C |
.0033 |
|
Group B versus Group C |
.6156 |
Full interpretation of the results
|
In: Math
A parabolic satellite dish reflects signals to the dish’s focal point. An antenna designer analyzed signals transmitted to a satellite dish and obtained the probability density function
f(x)=cæ1- 1 x2öfor 0<x<2,whereXisthedistance(inmeters)fromthecentroidofthe ç 16 ÷
èø
dish surface to a reflection point at which a signal arrives. Determine the following:
Value of c that makes f (x) a valid probability density function
?(? < 0.4
?(0.1<?<0.4
?(?)
?(?)
In: Math
For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
A random sample of 5260 permanent dwellings on an entire
reservation showed that 1585 were traditional hogans.
(a) Let p be the proportion of all permanent dwellings
on the entire reservation that are traditional hogans. Find a point
estimate for p. (Round your answer to four decimal
places.)
(b) Find a 99% confidence interval for p. (Round your
answer to three decimal places.)
lower limit | |
upper limit |
Give a brief interpretation of the confidence interval.
1% of the confidence intervals created using this method would include the true proportion of traditional hogans.99% of the confidence intervals created using this method would include the true proportion of traditional hogans. 99% of all confidence intervals would include the true proportion of traditional hogans.1% of all confidence intervals would include the true proportion of traditional hogans.
(c) Do you think that np > 5 and nq > 5 are
satisfied for this problem? Explain why this would be an important
consideration.
No, the conditions are not satisfied. This is important because it allows us to say that p̂ is approximately binomial.No, the conditions are not satisfied. This is important because it allows us to say that p̂ is approximately normal. Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately binomial.Yes, the conditions are satisfied. This is important because it allows us to say that p̂ is approximately normal.
In: Math