Is the national crime rate really going down? Some sociologists say yes! They say that the reason for the decline in crime rates in the 1980s and 1990s is demographics. It seems that the population is aging, and older people commit fewer crimes. According to the FBI and the Justice Department, 70% of all arrests are of males aged 15 to 34 years.† Suppose you are a sociologist in Rock Springs, Wyoming, and a random sample of police files showed that of 31 arrests last month, 23 were of males aged 15 to 34 years. Use a 1% level of significance to test the claim that the population proportion of such arrests is the city different from 70%. Solve the problem using both the traditional method and the P-value method. Since the sampling distribution of p̂ is the normal distribution, you can use critical values from the standard normal distribution as shown in the table of critical values of the z distribution. (Round the test statistic and the critical value to two decimal places. Round the P-value to four decimal places.)

State your conclusion in the context of the application.

There is sufficient evidence at the 0.01 level to conclude that the true proportion of such arrests in the city differs from 70%.There is insufficient evidence at the 0.01 level to conclude that the true proportion of such arrests in the city differs from 70%.    

Compare your conclusion with the conclusion obtained by using the P-value method. Are they the same?

We reject the null hypothesis using the traditional method, but fail to reject using the P-value method.We reject the null hypothesis using the P-value method, but fail to reject using the traditional method.    The conclusions obtained by using both methods are the same.

A) If the statistical test performed on the data gives p = 0.001 in the case where the alternative hypothesis H1 is true, the resulting conclusion is (at 5% significance level)

Choose one:
1. right negative
2. false negative
3. right positive
4. false positive
5. True, but it is not known whether it is positive or negative
6. False, but it is not known whether it is positive or negative
7. positive, but it is not known whether it is right or wrong
8. negative, but it is not known whether it is right or wrong.

B) If the statistical test performed on the data gives p = 0.6 in the case where the null hypothesis H0 is true, the resulting conclusion is (at 5% significance level)

Choose one:
1. right negative
2. false negative
3. right positive
4. false positive
5. True, but it is not known whether it is positive or negative
6. False, but it is not known whether it is positive or negative
7. positive, but it is not known whether it is right or wrong
8. negative, but it is not known whether it is right or wrong.

C) If the statistical test performed on the data gives p = 0.003 in the case where the null hypothesis H0 is true, the resulting conclusion is (at 5% significance level)

Choose one:
1. right negative
2. false negative
3. right positive
4. false positive
5. True, but it is not known whether it is positive or negative
6. False, but it is not known whether it is positive or negative
7. positive, but it is not known whether it is right or wrong
8. negative, but it is not known whether it is right or wrong.

D) If the statistical test performed on the data gives p = 0.4 in the case where the null hypothesis H0 is false, the resulting conclusion is (at 5% significance level)

Choose one:
1. right negative
2. false negative
3. right positive
4. false positive
5. True, but it is not known whether it is positive or negative
6. False, but it is not known whether it is positive or negative
7. positive, but it is not known whether it is right or wrong
8. negative, but it is not known whether it is right or wrong.

Thank you so much if anyone can help me! I would need only the answers :)

The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 33 records of automobile driver fatalities in Kit Carson County, Colorado, showed that 18 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use α = 0.01. Solve the problem using both the traditional method and the P-value method. Since the sampling distribution of p̂ is the normal distribution, you can use critical values from the standard normal distribution as shown in the table of critical values of the z distribution. (Round the test statistic and the critical value to two decimal places. Round the P-value to four decimal places.)

State your conclusion in the context of the application.

There is sufficient evidence at the 0.01 level to conclude that the true proportion of driver fatalities related to alcohol is less than 77%.There is insufficient evidence at the 0.01 level to conclude that the true proportion of driver fatalities related to alcohol is less than 77%.    

Compare your conclusion with the conclusion obtained by using the P-value method. Are they the same?

We reject the null hypothesis using the P-value method, but fail to reject using the traditional method.The conclusions obtained by using both methods are the same.    We reject the null hypothesis using the traditional method, but fail to reject using the P-value method.

What are the design modeling actions that support creative design?

Arden and Plomin (2006) published a study reporting that IQ scores for boys are more variable than IQ scores for girls. A researcher would like to know whether this same phenomenon applies to other measures of cognitive ability. A standard cognitive skills test is given to a sample of n = 15 adolescent boys and a sample of n = 15 adolescent girls, and resulted in the following scores. Boys Girls 9 5 3 9 7 6 5 4 6 7 5 2 4 8 8 6 4 7 6 8 7 4 9 7 3 5 7 8 6 5 1) Calculate the mean and the standard deviation for each group. Boys: Girls: 2) Based on the means and the standard deviations, describe the differences in intelligence scores for boys and girls. A- The girl's mean intelligence score is HIGHER THAN, LOWER THAN, OR THE SAME AS that the boy's scores. B- The boys’ scores are AS VARIABLE AS, LESS VARIABLE THAN, OR MORE VARIABLE THAN the girls’ scores?

Last year, 57% of business owners gave a holiday gift to their employees. A survey of business owners conducted this year indicates that 45% plan to provide a holiday gift to their employees. Suppose the survey results are based on a sample of 80 business owners.

(a)

How many business owners in the survey plan to provide a holiday gift to their employees this year?

business owners

(b)

Suppose the business owners in the sample did as they plan. Compute the p-value for a hypothesis test that can be used to determine if the proportion of business owners providing holiday gifts has decreased from last year.

Find the value of the test statistic. (Round your answer to two decimal places.)

Find the p-value. (Round your answer to four decimal places.)

p-value =

(c)

Using a 0.05 level of significance, would you conclude that the proportion of business owners providing gifts decreased?

Reject H₀. There is insufficient evidence to conclude that the proportion of business owners providing holiday gifts has decreased from last year.

Do not reject H₀. There is insufficient evidence to conclude that the proportion of business owners providing holiday gifts has decreased from last year.    

Do not reject H₀. There is sufficient evidence to conclude that the proportion of business owners providing holiday gifts has decreased from last year.

Reject H₀. There is sufficient evidence to conclude that the proportion of business owners providing holiday gifts has decreased from last year.

What is the smallest level of significance for which you could draw such a conclusion? (Round your answer to four decimal places.)

What is the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 9?

1. ) An instructor believes that students do not retain as much information from a lecture on a Friday compared to a Monday. To test this belief, the instructor teaches a small sample of college students some preselected material from a single topic on statistics on a Friday and on a Monday. All students received a test on the material. The differences in exam scores for material taught on Friday minus Monday are listed in the following table.

(a) Find the confidence limits at a 95% CI for these related samples. (Round your answers to two decimal places.)
to

(b) Can we conclude that students retained more of the material taught in the Friday class?

Yes, because 0 lies outside of the 95% CI.No, because 0 is contained within the 95% CI.    

2;) Listening to music has long been thought to enhance intelligence, especially during infancy and childhood. To test whether this is true, a researcher records the number of hours that eight high-performing students listened to music per day for 1 week. The data are listed in the table.

(a) Find the confidence limits at a 95% CI for this one-independent sample. (Round your answers to two decimal places.)
to  hours per day

(b) Suppose the null hypothesis states that students listen to 3.5 hours of music per day. What would the decision be for a two-tailed hypothesis test at a 0.05 level of significance?

Retain the null hypothesis because the value stated in the null hypothesis is within the limits for the 95% CI.Reject the null hypothesis because the value stated in the null hypothesis is outside the limits for the 95% CI.    Reject the null hypothesis because the value stated in the null hypothesis is within the limits for the 95% CI.Retain the null hypothesis because the value stated in the null hypothesis is outside the limits for the 95% CI.

A website has the following policy for creating a password:

• Passwords must be exactly 8 characters in length.

• Passwords must include at least one letter (a-z, A-Z) or supported special character (@, #, $ only). All letters are case-sensitive.

• Passwords must include at least one number (0-9).

• Passwords cannot contain spaces or unsupported special characters

According to this policy, how many possible passwords are available? (Round to the nearest trillion)

Question 4 Use your TI83 (or Excel): A normally distributed population of IQ scores has a mean of 99 and a standard deviation of 17. Determine the IQ at the 2nd percentile. Round to the nearest whole number

QUESTION 5 Use your TI83 (or Excel): A normally distributed population has a mean of 271 and a standard deviation of 28. Determine the value of the 90th percentile. Round to the nearest whole number

QUESTION 6 Use your TI83 (or Excel): A normally distributed population has a mean of 98.11 and a standard deviation of 0.22. Determine the value of the third quartile. Round to the nearest hundredth

QUESTION 7 Use your TI83 (or Excel): A normally distributed population has a mean of 98.37 and a standard deviation of 0.39. Determine the value of the first quartile. Round to the nearest hundredth

QUESTION 8 Use your TI83 (or Excel): A normally distributed population has a mean of 110 and a standard deviation of 19. Determine the value of the third quartile. Round to the nearest tenth

The probability that a house in an urban area will develop a leak is 6​%.If 44 houses are randomly​ selected, what is the probability that none of the houses will develop a​ leak? Round to the nearest thousandth.

• eBook

Refer to the gasoline sales time series data in the given table.

Anystate Auto Insurance Company took a random sample of 374 insurance claims paid out during a 1-year period. The average claim paid was $1530. Assume σ = $230. Find a 0.90 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit $ upper limit $ Find a 0.99 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit $ upper limit

I will be grateful to be answered using excell

You have to include the Excel formulas used.

In an evaluation of progress, made to 400 managers, the average of the scores was 70 and its standard deviation was 8.0, what is the probability that, if we select a manager at random (among the 400 that were evaluated ), did he get 70 or more?

Z                              =             __________________________

1-Z                          +             __________________________

Probability          =             __________________________ = ____________________%