Questions
Joan's Nursery specializes in custom-designed landscaping for residential areas. The estimated labor cost associated with a...

Joan's Nursery specializes in custom-designed landscaping for residential areas. The estimated labor cost associated with a particular landscaping proposal is based on the number of plantings of trees, shrubs, and so on to be used for the project. For cost-estimating purposes, managers use two hours of labor time for the planting of a medium-sized tree. Actual times from a sample of 10 plantings during the past month follow (times in hours).

1.8 1.4 2.7 2.1 2.4 2.3 2.6 3.0 1.4 2.3

With a 0.05 level of significance, test to see whether the mean tree-planting time differs from two hours.

(a)State the null and alternative hypotheses.

a)H0: μ ≤ 2

Ha: μ > 2

b)H0: μ < 2

Ha: μ ≥ 2

c)H0: μ = 2

Ha: μ ≠ 2

d)H0: μ ≥ 2

Ha: μ < 2

e)H0: μ > 2

Ha: μ ≤ 2

(b)Compute the sample mean.

(c)Compute the sample standard deviation. (Round your answer to three decimal places.)

(d)What is the test statistic? (Round your answer to three decimal places.)

test statistic=

What is the p-value? (Round your answer to four decimal places.)

p-value =

(e)What is your conclusion?

Do not reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.

Reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes.    

Do not reject H0. We cannot conclude that the mean tree-planting time differs from two hours. There is no reason to change from the two hours for cost estimating purposes.

Reject H0. We can conclude that the mean tree-planting time differs from two hours. There is a reason to change from the two hours for cost estimating purposes.

In: Math

Suppose you work for a survey research company. In a typical survey, you mail questionnaires to...

Suppose you work for a survey research company. In a typical survey, you mail questionnaires to 150 companies. Of course, some of these companies might decide not to respond. Assume that the nonresponse rate is 45%; that is, each company's probability of not responding, independently of the others, is 0.45. Round your answers to three decimal places and if your answer is zero, enter "0". a. If your company requires at least 90 responses for a valid survey, find the probability that it will get this many. Use a data table to see how your answer varies as a function of the nonresponse rate (for a reasonable range of response rates surrounding 45%).

I cannot get a table to work with the probabilities for

25%
30%
35%
40%
45%
50%
55%
60%
65%

In: Math

Loss,x1,x2 372,45,162 206,55,233 175,61,232 154,66,231 136,71,231 112,71,237 55,81,224 45,86,219 221,53,203 166,60,189 164,64,210 113,68,210 82,79,196 32,81,180 228,56,200...

Loss,x1,x2
372,45,162
206,55,233
175,61,232
154,66,231
136,71,231
112,71,237
55,81,224
45,86,219
221,53,203
166,60,189
164,64,210
113,68,210
82,79,196
32,81,180
228,56,200
196,68,173
128,75,188
97,83,161
64,88,119
249,59,161
219,71,151
186,80,165
155,82,151
114,89,128
341,51,161
340,59,146
283,65,148
267,74,144
215,81,134
148,86,127

I am asking the R studio Code, pleas leave your code and comment here, thanks a lot!

Q1.The data file abrasion contains the results from a small scale study (Davies, O.L. and Goldsmith, P.L. Statistical methods in Research and Production, 1972),  of the relation between rubber's resistance to abrasion (Y) and rubber hardness (X1) and rubber tensile strength (X2).

The data set abrasion is in Course Content -> Data Sets AL -> Ch04

  • Import the data set into R.
  • Obtain the scatter plot matrix and the correlation matrix.You can do this together using the commands in the file pairs.r

Upload the results here (one file in .png or .pdf formats) - Remember to include a title.

Q2.

Run the regression model. Obtain the estimates of the coefficients (round answer to 4 decimal places, it the answer is 7.5e-08 enter 0)

Coefficient estimate se p-value
b0 __ __ __
b1 __ __ __
b2 __ __ __

Which variable is significant? __ (enter exactly on of the three options: x1, x2 or both)

Q3.

Enter here the coefficient of determination (adjusted R-squared). Round your answer to 4 decimal places.

Q4.

Enter here the estimate for σ, that is s or the residual standard error. Round your answer to 2 decimal places.

Q5.

Use your model to obtain the mean abrasion loss for rubber with hardness 71 an tensile strength 201. Round your answer to 2 decimal places.

Q6.

Use your model to obtain a 98% confidence interval for the mean abrasion loss for rubber with hardness 71 an tensile strength 201.

Enter here the Lower Bound for the confidence interval. Round your answer to 2 decimal places.

Q7.

After the scatter plots, the correlation between the variables, the summary of the model, R-squared and s, and the F-test, briefly comment on the adequacy of the model fit.

In: Math

You may need to use the appropriate technology to answer this question. Health insurance benefits vary...

You may need to use the appropriate technology to answer this question.

Health insurance benefits vary by the size of the company. The sample data below show the number of companies providing health insurance for small, medium, and large companies. For purposes of this study, small companies are companies that have fewer than 100 employees. Medium-sized companies have 100 to 999 employees, and large companies have 1,000 or more employees.

The questionnaire sent to 225 employees asked whether or not the employee had health insurance and then asked the employee to indicate the size of the company.

Health Insurance Size of the Company
Small Medium Large
Yes 30 59 82
No 20 16 18

(a)

Conduct a test of independence to determine whether health insurance coverage is independent of the size of the company.

State the null and alternative hypotheses.

H0: Having health insurance is not independent of the size of the company.
Ha: Having health insurance is independent of the size of the company. H0: Having health insurance is not independent of the size of the company.
Ha: The proportion of companies with health insurance benefits is not equal for small, medium and large companies.     H0: Having health insurance is independent of the size of the company.
Ha: The proportion of companies with health insurance benefits is equal for small, medium and large companies.H0: Having health insurance is independent of the size of the company.
Ha: Having health insurance is not independent of the size of the company.

Find the value of the test statistic. (Round your answer to three decimal places.)

What is the p-value? (Round your answer to four decimal places.)

p-value =

Using a 0.05 level of significance, what is your conclusion?

Do not reject H0. We cannot conclude health insurance coverage and the size of the company are not independent.Do not reject H0. We cannot conclude health insurance coverage is independent of the size of the company.     Reject H0. We conclude health insurance coverage is independent of the size of the company. Reject H0. We conclude health insurance coverage is not independent of the size of the company.

(b)

A newspaper article indicated employees of small companies are more likely to lack health insurance coverage. Use percentages based on the above data to support this conclusion. (Round your answers to the nearest integer.)

For small companies,  % do not provide health insurance. For medium companies,  % do not provide health insurance. For large companies,  % do not provide health insurance. These percentages support the conclusion that small companies are  ---Select--- less more equally likely to provide health insurance coverage when compared to medium and large companies.

In: Math

A population consists of the following N=6 scores: 2,4,1,2,7,2 a) compute mean and standard deviation for...

A population consists of the following N=6 scores: 2,4,1,2,7,2 a) compute mean and standard deviation for the population b)Find z-score for each score in the population c) Transform the original population into a new population of N=5 scores with a mean of M(mu)=50 and a standard deviation of sigma=10?

In: Math

You may need to use the appropriate technology to answer this question. A standardized exam consists...

You may need to use the appropriate technology to answer this question.

A standardized exam consists of three parts: math, writing, and critical reading. Sample data showing the math and writing scores for a sample of 12 students who took the exam follow.

Student Math Writing
1 540 474
2 432 380
3 528 463
4 574 612
5 448 420
6 502 526
7 480 430
8 499 459
9 610 609
10 572 541
11 390 329
12 593 613

(a)

Use a 0.05 level of significance and test for a difference between the population mean for the math scores and the population mean for the writing scores. (Use math score − writing score.)

Formulate the hypotheses.

H0: μd > 0

Ha: μd ≤ 0

H0: μd ≤ 0

Ha: μd > 0

     

H0: μd ≠ 0

Ha: μd = 0

H0: μd = 0

Ha: μd ≠ 0

H0: μd ≤ 0

Ha: μd = 0

Calculate the test statistic. (Round your answer to three decimal places.)

Calculate the p-value. (Round your answer to four decimal places.)

p-value =

What is your conclusion?

Do not reject H0. We cannot conclude that there is a significant difference between the population mean scores for the math test and the writing test. Reject H0. We cannot conclude that there is a significant difference between the population mean scores for the math test and the writing test.      Reject H0. We can conclude that there is a significant difference between the population mean scores for the math test and the writing test. Do not reject H0. We can conclude that there is a significant difference between the population mean scores for the math test and the writing test.

(b)

What is the point estimate of the difference between the mean scores for the two tests? (Use math score − writing score.)

What are the estimates of the population mean scores for the two tests?

Math Writing

Which test reports the higher mean score?

The math test reports a  ---Select--- higher lower mean score than the writing test.

In: Math

Filling boxes with consistent amounts of its cereals is critical to General Mills's success. The filling...

Filling boxes with consistent amounts of its cereals is critical to General Mills's success. The filling variance for boxes of Count Chocula cereal is designed to be 0.02 ounces2 or less. A sample of 31 boxes of Count Chocula shows a sample standard deviation of 0.16 ounces. Use α = 0.05 to determine whether the variance in the cereal box fillings is exceeding the design specification.

A) State the null and alternative hypotheses.

a) H0: σ2 = 0.02

Ha: σ2 ≠ 0.02

b) H0: σ2 < 0.02

Ha: σ2 ≥ 0.02

c) H0: σ2 ≥ 0.02

Ha: σ2 < 0.02

d) H0: σ2 ≤ 0.02

Ha: σ2 > 0.02

e) H0: σ2 > 0.02

Ha: σ2 ≤ 0.02

B) Find the value of the test statistic.

test statistic=

Find the p-value. (Round your answer to four decimal places.)

p-value =

State your conclusion.

Reject H0. The population variance does appear to be exceeding the standard.

Reject H0. The population variance does not appear to be exceeding the standard.    

Do not reject H0. The population variance does appear to be exceeding the standard.

Do not reject H0. The population variance does not appear to be exceeding the standard

In: Math

You may need to use the appropriate technology to answer this question. Based on sales over...

You may need to use the appropriate technology to answer this question.

Based on sales over a six-month period, the five top-selling compact cars are Chevy Cruze, Ford Focus, Hyundai Elantra, Honda Civic, and Toyota Corolla.† Based on total sales, the market shares for these five compact cars were Chevy Cruze 24%, Ford Focus 21%, Hyundai Elantra 20%, Honda Civic 18%, and Toyota Corolla 17%. Suppose a sample of 400 compact car sales in one city showed the following number of vehicles sold.

Chevy Cruze 107
Ford Focus 93
Hyundai Elantra 63
Honda Civic 84
Toyota Corolla 53

Use a goodness of fit test to determine if the sample data indicate that the market shares for the five compact cars in this city are different than the market shares reported by Motor Trend. Use a 0.05 level of significance.

State the null and alternative hypotheses.

H0: The majority of the market shares for the five automobiles in this city differ from the ones reported by Motor Trend.
Ha: The majority of the market shares for the five automobiles in this city are the same as the ones reported by Motor Trend.H0: The market shares for the five automobiles in this city differ from 0.24, 0.21, 0.20, 0.18, 0.17.
Ha: The market shares for the five automobiles in this city are the same as the above shares.     H0: The majority of the market shares for the five automobiles in this city are the same as the ones reported by Motor Trend.
Ha: The majority of the market shares for the five automobiles in this city differ from the ones reported by Motor Trend.H0: The market shares for the five automobiles in this city are 0.24, 0.21, 0.20, 0.18, 0.17.
Ha: The market shares for the five automobiles in this city differ from the above shares.

Find the value of the test statistic. (Round your answer to three decimal places.)

Find the critical value for the test. (Round your answer to three decimal places.)

critical value =

State your conclusion.

Reject H0. We cannot conclude that the market shares for the five compact cars in this city differ from the market shares reported. Do not reject H0. We conclude that the market shares for the five compact cars in this city differ from the market shares reported.      Do not reject H0. We cannot conclude that the market shares for the five compact cars in this city differ from the market shares reported. Reject H0. We conclude that the market shares for the five compact cars in this city differ from the market shares reported.

What market share differences, if any, exist in this city?

Chevy Cruze shows  ---Select--- a higher a lower the same market share in this city. Ford Focus shows  ---Select--- a higher a lower the same market share in this city. Hyundai Elantra shows  ---Select--- a higher a lower the same market share in this city. Honda Civic shows  ---Select--- a higher a lower the same market share in this city. Toyota Corolla shows  ---Select--- a higher a lower the same market share in this city.

In: Math

You may need to use the appropriate technology to answer this question. The College Board provided...

You may need to use the appropriate technology to answer this question.

The College Board provided comparisons of Scholastic Aptitude Test (SAT) scores based on the highest level of education attained by the test taker's parents. A research hypothesis was that students whose parents had attained a higher level of education would on average score higher on the SAT. The overall mean SAT math score was 514.† SAT math scores for independent samples of students follow. The first sample shows the SAT math test scores for students whose parents are college graduates with a bachelor's degree. The second sample shows the SAT math test scores for students whose parents are high school graduates but do not have a college degree.

College Grads
501 471
534 549
634 526
554 410
534 515
556 578
513 464
592 469
High School Grads
442 492
580 478
479 425
486 485
528 390
524 535

(a)

Formulate the hypotheses that can be used to determine whether the sample data support the hypothesis that students show a higher population mean math score on the SAT if their parents attained a higher level of education. (Let μ1 = population mean verbal score of students whose parents are college graduates with a bachelor's degree and μ2 = population mean verbal score of students whose parents are high school graduates but do not have a college degree.) For purposes of this study, assume the population variances are unequal when conducting the t-test.

H0: μ1μ2 < 0

Ha: μ1μ2 = 0

H0: μ1μ2 = 0

Ha: μ1μ2 ≠ 0

     

H0: μ1μ2 ≠ 0

Ha: μ1μ2 = 0

H0: μ1μ2 ≥ 0

Ha: μ1μ2 < 0

H0: μ1μ2 = 0

Ha: μ1μ2 > 0

(b)

What is the point estimate of the difference between the means for the two populations?

(c)

Find the value of the test statistic. (Round your answer to three decimal places.)

Compute the p-value for the hypothesis test. (Round your answer to four decimal places.)

p-value =

(d)

At

α = 0.05,

what is your conclusion?

Do not reject H0. There is insufficient evidence to conclude that higher population mean verbal scores are associated with students whose parents are college graduates.Do not Reject H0. There is sufficient evidence to conclude that higher population mean verbal scores are associated with students whose parents are college graduates.      Reject H0. There is insufficient evidence to conclude that higher population mean verbal scores are associated with students whose parents are college graduates.Reject H0. There is sufficient evidence to conclude that higher population mean verbal scores are associated with students whose parents are college graduates.

In: Math

5. Arsalaan A., a well-known financial analyst, selected 50 consecutive years of U.S. financial markets data...

5. Arsalaan A., a well-known financial analyst, selected 50 consecutive years of U.S. financial markets data at random. For 11 of the years, the rate of return for the Dow Jones Industrial Average [DJIA] exceeded the rates of return for both the S&P 500 Index and the NASDAQ Composite Index. For 8 of the years, the rate of return for the DJIA trailed the rates of return for both the S&P 500 and the NASDAQ. For 21 of the years, the rate of return for the DJIA trailed the rate of return for the S&P 500. Over the 50 years,

a. determine the probability the rate of return for the DJIA trailed the rate of return for the NASDAQ.

b. determine the probability the rate of return for the DJIA trailed the rate of return for at least one of the other two Indexes.

c. determine the probability the rate of return for the DJIA trailed the rate of return for the S&P 500 given it trailed the rate of return for the NASDAQ.

d. determine the probability the rate of return for the DJIA exceeded the rate of return for the S&P 500 given it exceeded the rate of return for the NASDAQ

In: Math

A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly...

  1. A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly located on those pages. Find the probability that a random selection of 50 pages will contain no errors. Find the probability that 50 randomly selected pages will contain at least two errors.

In: Math

A report states that adults 18- to 24- years-old send and receive 128 texts every day....

A report states that adults 18- to 24- years-old send and receive 128 texts every day. Suppose we take a sample of 25- to 34- year-olds to see if their mean number of daily texts differs from the mean for 18- to 24- year-olds.

(a) State the null and alternative hypotheses we should use to test whether the population mean daily number of texts for 25- to 34-year-olds differs from the population daily mean number of texts for 18- to 24-year-olds. (Enter != for ≠ as needed.)

H0:

Ha:

(b) Suppose a sample of thirty 25- to 34-year-olds showed a sample mean of 118.9 texts per day. Assume a population standard deviation of 33.17 texts per day.

Compute the p-value. (Round your answer to four decimal places.)

p-value =

(c) With α = 0.05 as the level of significance, what is your conclusion?

(d) Repeat the preceding hypothesis test using the critical value approach.

State the null and alternative hypotheses. (Enter != for ≠ as needed.)

H0:

Ha:

(e) Find the value of the test statistic. (Round your answer to two decimal places.)

State the critical values for the rejection rule. (Use α = 0.05. Round your answer to two decimal places. If the test is one-tailed, enter NONE for the unused tail.)

test statistic≤

test statistic≥

(f)

State your conclusion.

Do not reject H0. We cannot conclude that the population mean daily texts for 25- to 34-year-olds differs significantly from the population mean of 128 daily texts for 18- 24-year-olds.

Reject H0. We cannot conclude that the population mean daily texts for 25- to 34-year-olds differs significantly from the population mean of 128 daily texts for 18- 24-year-olds.   

Do not reject H0. We can conclude that the population mean daily texts for 25- to 34-year-olds differs significantly from the population mean of 128 daily texts for 18- 24-year-olds.

Reject H0. We can conclude that the population mean daily texts for 25- to 34-year-olds differs significantly from the population mean of 128 daily texts for 18- 24-year-olds.

In: Math

Problem 15. Give an example of a two mutually exclusive events. Problem 16. Give an example...

Problem 15. Give an example of a two mutually exclusive events.

Problem 16. Give an example of three events E, F, and G so that each pair of events is mutually exclusive

Problem 17. Consider a situation where #(all) = 100, #(E) = 32, #(F) = 52, and #(E ∩ F) = 13. 1. Find P(E | F). 2. Calculate #(E ∩ F) #(F) and explain why this matches the value in part 1. Problem 18. Suppose we have 30 shuffled cards numbered 1-30. What is the probability of drawing an even value given that the value is greater than 9?

Problem 19. Suppose we roll a 6-sided die two times. What is the probability of the sum of the values being greater than 7 given that the first roll was a 5?

In: Math

Discussion: Central Tendency and Variability Understanding descriptive statistics and their variability is a fundamental aspect of...

Discussion: Central Tendency and Variability Understanding descriptive statistics and their variability is a fundamental aspect of statistical analysis. On their own, descriptive statistics tell us how frequently an observation occurs, what is considered “average”, and how far data in our sample deviate from being “average.” With descriptive statistics, we are able to provide a summary of characteristics from both large and small datasets. In addition to the valuable information they provide on their own, measures of central tendency and variability become important components in many of the statistical tests that we will cover. Therefore, we can think about central tendency and variability as the cornerstone to the quantitative structure we are building. For this Discussion, you will examine central tendency and variability based on two separate variables. You will also explore the implications for positive social change based on the results of the data. To prepare for this Discussion: Review this week’s Learning Resources and the Descriptive Statistics media program. For additional support, review the Skill Builder: Visual Displays for Categorical Variables and the Skill Builder: Visual Displays for Continuous Variables, which you can find by navigating back to your Blackboard Course Home Page. From there, locate the Skill Builder link in the left navigation pane. Review the Chapter 4 of the Wagner text and the examples in the SPSS software related to central tendency and variability. From the General Social Survey dataset found in this week’s Learning Resources, use the SPSS software and choose one continuous and one categorical variable Note: this dataset will be different from your Assignment dataset). As you review, consider the implications for positive social change based on the results of your data.

For your continuous variable: 1. Report the mean, median, and mode. 2. What might be the better measure for central tendency? (i.e., mean, median, or mode) and why? 3. Report the standard deviation. 4. How variable are the data? 5. How would you describe this data? 6. What sort of research question would this variable help answer that might inform social change? Post the following information for your categorical variable: 1. A frequency distribution. 2. An appropriate measure of variation. 3. How variable are the data? 4. How would you describe this data? 5. What sort of research question would this variable help answer that might inform social change?

In: Math

Prove that if two of the opposite sides of a quadrilateral are respectively the greatest and...

Prove that if two of the opposite sides of a quadrilateral are respectively the greatest and the least sides of the quadrilateral, then the angles adjacent to the least are greater than their opposite angles.

In: Math