In: Math
Assume that the distribution of starting salaries for newly qualified CA’s is approximately Normal and has a std deviation of $2,500. We have a random sample of 16 CA’s.
a) Find the probability that the std error (sample std deviation) > $3000.
b) Find the probability that the std error (sample std deviation) < $1500.
a)
Sample Size, n= 16
Standard Deviation, σ= 2500
P ( s > 3000 ) = 1 - P( s ≤ 3000)=1 -
P(X²≤(n-1)s²/σ²) = 1 - P(X² ≤ 15*3000²/2500² )
=1 - P(X² ≤ 21.6 )
=1 - 0.88127 =
0.1187
[excel function: "=1 - CHISQ.DIST(21.6,15,TRUE)
b)
Sample Size, n= 16
population Standard Deviation, σ= 2500
P ( s< 1500 )= P(X²≤(n-1)s²/σ²) =
=P(X² < 5.4 ) =
0.0118
[excel function: "=CHISQ.DIST(5.4,15,TRUE) ]