In: Statistics and Probability
In this problem, assume that the distribution of differences is
approximately normal. Note: For degrees of freedom
d.f. not in the Student's t table, use
the closest d.f. that is smaller. In
some situations, this choice of d.f. may increase
the P-value by a small amount and therefore produce a
slightly more "conservative" answer.
Are America's top chief executive officers (CEOs) really worth all
that money? One way to answer this question is to look at row
B, the annual company percentage increase in revenue,
versus row A, the CEO's annual percentage salary increase
in that same company. Suppose a random sample of companies yielded
the following data:
B:
Percent increase for company |
22 | 6 | 12 | 18 | 6 | 4 | 21 | 37 |
A:
Percent increase for CEO |
25 | 27 | 26 | 14 | -4 | 19 | 15 | 30 |
Do these data indicate that the population mean percentage increase in corporate revenue (row B) is different from the population mean percentage increase in CEO salary? Use a 5% level of significance. (Let d = B ? A.)
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: ?d = 0; H1: ?d < 0H0: ?d > 0; H1: ?d = 0 H0: ?d ? 0; H1: ?d = 0H0: ?d = 0; H1: ?d > 0H0: ?d = 0; H1: ?d ? 0
(b) What sampling distribution will you use? What assumptions are
you making?
The Student's t. We assume that d has an approximately normal distribution.The Student's t. We assume that d has an approximately uniform distribution. The standard normal. We assume that d has an approximately uniform distribution.The standard normal. We assume that d has an approximately normal distribution.
What is the value of the sample test statistic? (Round your answer
to three decimal places.)
(c) Find the P-value. (Round your answer to four decimal
places.)
Sketch the sampling distribution and show the area corresponding to
the P-value.
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level ??
Since the P-value ? ?, we reject H0. The data are statistically significant.Since the P-value > ?, we fail to reject H0. The data are not statistically significant. Since the P-value > ?, we reject H0. The data are not statistically significant.Since the P-value ? ?, we fail to reject H0. The data are statistically significant.
(e) Interpret your conclusion in the context of the
application.
Reject H0. At the 5% level of significance, the evidence is sufficient to claim a difference in population mean percentage increases for corporate revenue and CEO salary.Fail to reject H0. At the 5% level of significance, the evidence is insufficient to claim a difference in population mean percentage increases for corporate revenue and CEO salary. Fail to reject H0. At the 5% level of significance, the evidence is sufficient to claim a difference in population mean percentage increases for corporate revenue and CEO salary.Reject H0. At the 5% level of significance, the evidence is insufficient to claim a difference in population mean percentage increases for corporate revenue and CEO salary.
(a) What is the level of significance?
Level of significance = = 0.05
State the null and alternate hypotheses.
Here we want to test the population mean percentage increase in corporate revenue (row B) is different from the population mean percentage increase in CEO salary. So the correct option is
H0: ?d= 0; H1: ?d ? 0
(b) What sampling distribution will you use? What assumptions are you making?
The Student's t. We assume that d has an approximately normal distribution
Because population standard deviation are not given.
What is the value of the sample test statistic? (Round your answer to three decimal places.)
Let's use minitab:
Let's used minitab:
Enter the given data set in minitab columns
Steps 1) Click on Stat>>>Basic Statistics>>>2-Sample t...
Steps 2) Click on sample in different columns
look the following picture.
then click on OK again click on OK
So we get the following output
From the above output the t test statistic value is
t = 0.589
c) P -value = 0.5653
d)
Decision rule:
1) If p-value < level of significance (alpha) then we reject null hypothesis
2) If p-value > level of significance (alpha) then we fail to reject null hypothesis.
Here p value = 0.5653 > 0.05 so we used 2nd rule.
That is we fail to reject null hypothesis
Since the P-value > ?, we fail to reject H0. The data are not statistically significant.
(e) Interpret your conclusion in the context of the
application.
Fail to reject H0. At the 5% level of significance, the evidence is insufficient to claim a difference in population mean percentage increases for corporate revenue and CEO salary.