In: Physics
The circuit shown in the figure below, called the Wheatstone bridge, is used to determine the value of unknown resistor Xby comparison with three resistors M, N, and P whose resistances can be varied. For each setting, the resistance of each resistor is precisely known. With switches K1 and K2 closed, these resistors are varied until the current in the galvanometer G is zero; the bridge is then said to be balanced.
(a) Show that under this condition the unknown resistance is
given by X = MP/N. (This method permits
very high precision in comparing resistors.) (Do this on paper.
Your instructor may ask you to turn in this work.)
(b) If the galvanometer G shows zero deflection when M =
829.0 Ω, N = 15.20 Ω, and P = 33.48 Ω, what is
the unknown resistance X?
Ω
Zero current through the galvanometer means the current I1 through N is also the current through M and the current I2 through P is the same as the current through X. And it means that points b and c are at the same potential,
so I1*N = I2*P.
The voltage between points a and d is E
I1 = E/(N+M)
I2 = E/(P+X)
I1*N = I2*P
(E/(N+M))*N = ( E/(P+X))*P
N*(P+X) = P(N+M)
NX = PM
X = PM/N
B.
X = 33.48*829/(15.20) = 1825.98 ohm