In: Chemistry
1. For the reaction in the previous problem, that is,
2HI(g) ↔ H2(g) + I2(g) Keq = 0.016
Initially a container contains 0.69 M HI and no product. What is
the equilibrium concentration of H2?
2. For the reaction:
2HBr(g) ↔ H2(g) + Br2(g)
Initially a container contains 0.87 M HBr and no product. What is
the equilibrium concentration of HBr if the equilibrium
concentration of H2 is 0.16 M? (Hint provided in feedback.)
1)
ICE Table:
[HI]
[H2]
[I2]
initial
0.69
0
0
change -2x +1x +1x
equilibrium 0.69-2x +1x +1x
Equilibrium constant expression is
Kc = [H2]*[I2]/[HI]^2
0.016 = (1*x)^2/(0.69-2*x)^2
sqrt(0.016) = (1*x)/(0.69-2*x)
0.1265 = (1*x)/(0.69-2*x)
0.08728-0.25298*x = 1*x
0.08728-1.25298*x = 0
x = 0.06966
At equilibrium:
[H2] = x = 0.06966 M
Answer: 0.070 M
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