In: Statistics and Probability
| 
 Credits  | 
| 
 13  | 
| 
 12  | 
| 
 6  | 
| 
 9  | 
| 
 15  | 
| 
 9  | 
| 
 15  | 
| 
 15  | 
| 
 13  | 
| 
 16  | 
| 
 15  | 
| 
 10  | 
| 
 12  | 
| 
 16  | 
| 
 15  | 
| 
 10  | 
| 
 13  | 
| 
 15  | 
| 
 6  | 
| 
 13  | 
| 
 7  | 
| 
 9  | 
| 
 12  | 
| 
 13  | 
| 
 16  | 
| 
 8  | 
| 
 4  | 
| 
 10  | 
| 
 13  | 
| 
 15  | 
| 
 12  | 
| 
 13  | 
| 
 3  | 
| 
 10  | 
| 
 13  | 
| 
 16  | 
| 
 12  | 
| 
 10  | 
| 
 14  | 
| 
 13  | 
From the data we can see that there are 26 students enrolled in
12 or more credits in a
semester       
Total number of students =
40       
a) Let p = proportion of students from the respondents that are
full-time students       
p = 26/40 = 0.65 =
65%       
Percent of respondents in the student dataset are
“full-time” students =
65%       
        
b) n = 20 sample class of 20
students      
p = 0.65 best estimate for probability of randomly selected student
being full-time      
Let X be the number of students being full-time in the class of 20
students       
X ~ Binomial distribution with n = 20 and p =
0.65       
To find P(X=20)       
We use the Excel function BINOM.DIST to find the
probability       
P(X=20) =
BINOM.DIST(20,20,0.65,FALSE)       
                
= 0.000181       
P(in a class of 20 students they will all be full-time) =
0.000181