Question

In: Statistics and Probability

A student at a junior college conducted a survey of 20 randomly selected​ full-time students to...

A student at a junior college conducted a survey of 20 randomly selected​ full-time students to determine the relation between the number of hours of video game playing each​ week, x, and​ grade-point average, y. She found that a linear relation exists between the two variables. The​ least-squares regression line that describes this relation is ModifyingAbove y with caret equals negative 0.0559 x plus 2.9289.

(a) Predict the​ grade-point average of a student who plays video games 8 hours per week.

The predicted​ grade-point average is

​(Round to the nearest hundredth as​ needed.)

​(b) Interpret the slope.

For each additional hour that a student spends playing video games in a​ week, the​ grade-point average will

decrease / increase / nothing

by ____​points, on average.

​(c) If​ appropriate, interpret the​ y-intercept.

A.The​ grade-point average of a student who does not play video games is

2.92892.9289.

B.The average number of video games played in a week by students is

2.92892.9289.

C. It cannot be interpreted without more information.

(d) A student who plays video games 7 hours per week has a​ grade-point average of

2.632.63. Is the​ student's grade-point average above or below average among all students who play video games 7 hours per​ week?

The​ student's grade-point average is

above/ below

average for those who play video games 7 hours per week.

Solutions

Expert Solution

Given regression equation is y = - 0.0559x + 2.9289.

(A) grade-point average of a student who plays video games 8 hours per week, i.e. put x = 8 in the regression equation

this implies

= - 0.0559*8 + 2.9289.

= -0.4472 + 2.9289

= 2.48

(B) Slope is -0.0559, negative sign indicates decrease in dependent variable with increase in independent variable

So,

For each additional hour that a student spends playing video games in a​ week, the​ grade-point average will

decrease by __-0.0559__​points, on average

(C) Intercept is denote the value of dependent variable y when independent variable x is 0

So, correct answer is option A

The​ grade-point average of a student who does not play video games is 2.9289.

(D) grade-point average of a student who plays video games 7 hours per week, i.e. put x = 7 in the regression equation

this implies

= - 0.0559*7 + 2.9289.

= -0.3913 + 2.9289

= 2.54

So, it is clear that average grade point for playing 7 hours video game is 2.54, which is less than 2.63

The​ student's grade-point average is above average for those who play video games 7 hours per week.


Related Solutions

A student at a junior college conducted a survey of 20 randomly selected? full-time students to...
A student at a junior college conducted a survey of 20 randomly selected? full-time students to determine the relation between the number of hours of video game playing each? week, x, and? grade-point average, y. She found that a linear relation exists between the two variables. The? least-squares regression line that describes this relation is y = -0.0503x + 2.9381. (a) Predict the grade-point average of a student who plays video games 8 hours per week. The predicted grade-point average...
A student at a junior college conducted a survey of 20 randomly selected​ full-time students to...
A student at a junior college conducted a survey of 20 randomly selected​ full-time students to determine the relation between the number of hours of video game playing each​ week, x, and​ grade-point average, y. She found that a linear relation exists between the two variables. The​ least-squares regression line that describes this relation is ModifyingAbove y with caret equals negative 0.0592 x plus 2.9446. ​(a) Predict the​ grade-point average of a student who plays video games 8 hours per...
A survey of 36 randomly selected students who dropped a course was conducted at a college....
A survey of 36 randomly selected students who dropped a course was conducted at a college. The following results were collected. Complete parts​ (a) through​ (c). a) Construct a contingency table for the two variables. CourseCourse PersonalPersonal WorkWork Male FemaleFemale ​(b) Test whether gender is independent of drop reason at the alphaαequals=0.1 level of significance. What are the​ hypotheses? A. Upper H 0H0​: pSubscript Upper CCequals=pSubscript Upper PPequals=pSubscript Upper WW Upper H 1H1​: At least one of the proportions is...
The table shows the weekly income of 2020 randomly selected​ full-time students. If the student did...
The table shows the weekly income of 2020 randomly selected​ full-time students. If the student did not​ work, a zero was entered. 0 463 0 0 501 103 527 231 329 385 3383 197 517 165 248 0 572 412 258 93 ​(a) Check the data set for outliers. ​(b) Draw a histogram of the data. ​(c) Provide an explanation for any outliers. ​List all the outliers in the given data set. Select the correct choice below and fill in...
In a time-use study, 20 randomly selected college students were found to spend a mean of...
In a time-use study, 20 randomly selected college students were found to spend a mean of 1.4 hours on the internet each day. The standard deviation of the 20 scores was 1.3 hours. Construct a 90% confidence interval for the mean time spent on the internet by college students. Assume t* = 1.729 If you increased the sample size for the problem above, what would happen to your confidence interval, assuming the sample mean and standard deviation remain unchanged?
The grade averages for 10 randomly selected junior college students are listed below. Assume the grade...
The grade averages for 10 randomly selected junior college students are listed below. Assume the grade averages are normally distributed. Find a 98% confidence interval for the true mean. 78 80 83 48 76 72 94 75 91 65
In a recent survey of 60 randomly selected college students, 43 said that they believe in...
In a recent survey of 60 randomly selected college students, 43 said that they believe in the existence of extraterrestrial life. a) Find p?, the sample proportion that believes that there is extraterrestrial life. (Round your answers to three decimal places). p? = b)The 99 % margin of error associated with this estimate is: c) The 99 % confidence interval for the true proportion of all college students who believe there is extraterrestrial life is: to d) A recent report...
Students at a college randomly selected 217 student cars and found that they had ages with...
Students at a college randomly selected 217 student cars and found that they had ages with a mean of 7.89 years and a standard deviation of 3.67 years. They also randomly selected 152 faculty cars and found that they had ages with a mean of 5399 years and a standard deviation of 3.65 years. a) Using a 0.05 significance level, are student cars older than faculty cars? List: Define the parameters u1 and u2 Null and Alternative Hypothesis P-value Initial...
A survey of 196 randomly selected college students at a local university found that only 78%...
A survey of 196 randomly selected college students at a local university found that only 78% of them checked their college email on a regular basis. The standard deviation is 7.4. Construct the confidence interval for the population proportion with a 90% confidence level.
A sample of 1000 college students at NC State University were randomly selected for a survey....
A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 108 students suggested that classes begin at 8 AM instead of 8:30 AM. The sample proportion is 0.108. What is the lower endpoint for the 90% confidence interval? Give your answer to three decimal places. (Note that due to the randomization of the questions, the numbers in this question might be different from the previous question.) Answer:
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT