In: Chemistry
1)Calculate the pH of a 0.200M solution of arsenic acid, H3AsO4.
H3AsO4 ----------------------> H+ + H2AsO4-
0.200 0 0
-x + x + x
0.2-x x x
Ka = x^2 / 0.2-x = 5.5 x 10^-3
x^2 + 5.5 x 10^-3 x - 1.1 x 10^-3 = 0
x = 0.0305
[H+] = 0.0305 M
pH = -log [0.0305]
pH = 1.52