In: Statistics and Probability
Using SAS programming Please include the syntax and output of the information:
In a study of factors thought to be responsible for the adverse effects of smoking on human reproduction, cadmium level determinations (nanograms per gram) were made on placenta tissue of a sample of 14 mothers who were smokers and an independent random sample of 18 nonsmoking mothers.
The results were as follows-
Nonsmokers: 10.0, 8.4, 12.8, 25.0, 11.8, 9.8, 12.5, 15.4, 23.5, 9.4, 25.1, 19.5, 25.5, 9.8, 7.5, 11.8, 12.2, 15.0
Smokers: 30.0, 30.1, 15.0, 24.1, 30.5, 17.8, 16.8, 14.8, 13.4, 28.5, 17.5, 14.4, 12.5, 20.4
Does it appear likely that the mean cadmium level is higher among smokers than nonsmokers? To answer this question, construct and interpret the 95% confidence interval estimate of the difference in means.
Use the 6 Step Hypothesis:
STEP 1: STATE THE APPROPRIATE NULL AND ALTERNATIVE HYPOTHESES
STEP 2: DEFINE THE CRITICAL REGION
STEP 3: COMPUTE THE APPROPRIATE TEST STATISTIC
STEP 4: STATE YOUR STATISTICAL DECISION
STEP 5: STATE YOUR PRACTICAL CONCLUSION
STEP 6: REPORT THE P-VALUE
The SAS syntax is as,
data smoke ;
input smoke_nonSmoke$ Values;
datalines;
Nonsmokers 10
Nonsmokers 8.4
Nonsmokers 12.8
Nonsmokers 25
Nonsmokers 11.8
Nonsmokers 9.8
Nonsmokers 12.5
Nonsmokers 15.4
Nonsmokers 23.5
Nonsmokers 9.4
Nonsmokers 25.1
Nonsmokers 19.5
Nonsmokers 25.5
Nonsmokers 9.8
Nonsmokers 7.5
Nonsmokers 11.8
Nonsmokers 12.2
Nonsmokers 15
Smokers 30
Smokers 30.1
Smokers 15
Smokers 24.1
Smokers 30.5
Smokers 17.8
Smokers 16.8
Smokers 14.8
Smokers 13.4
Smokers 28.5
Smokers 17.5
Smokers 14.4
Smokers 12.5
Smokers 20.4
;
run;
proc ttest data=smoke sides=2 alpha=0.05 h0=0;
title "Two sample t-test example";
class smoke_nonSmoke;
var Values;
run;
Output of the SAS as
Both For unequal and equal variances p-value is significant,
so conclusion is ,
there is significant change in smoker and nonsmoker woman's on the cadmium level .
Thanks
non smoker womens have less cadmium level than smoker women