In: Physics
I'm using this to study for an exam, please write out all steps and include formulas, thank you!
The world's fastest land animal, the cheetah, can accelerate at 8.75 m/s2 to a top speed of vcmax = 30.5 m/s. A cheetah observes a passing gazelle traveling at vg = 19.1 m/s and begins to chase it.
(a) How long, in seconds, does it take the
cheetah to reach its maximum velocity, vcmax,
assuming its acceleration is constant?
(b) How far, in meters, has the cheetah traveled,
dmax,vel, when it reaches it maximum
velocity?
(c) Assume that d is the distance the
cheetah is away from the gazelle when it reaches full speed. Derive
an expression in terms of the variables d,
vcmax and vg for the time,
tc, it takes the cheetah to catch the
gazelle.
(d) What is the numeric value for this time,
tc in seconds, assuming the cheetah is 32 m
away when it reaches maximum velocity?