Gene A with 3000 hydrogen bonds and the number of nucleotide Adenine is equal to Guanine,...

Gene A with 3000 hydrogen bonds and the number of nucleotide Adenine is equal to Guanine, is mutated to gene a. When gene a underwent DNA replication, the environment provided 2398 nucleotides. Which kind of mutation that gene A had?

Expert Solution

According to Chargoff's rule the number of Purines will be equal to the number of pyramidines and vice versa. Here, it is geven that the number of both the purines Adenine and Guanine are equal in number. So, it can be deduced that the number of Cytosine and Thymine should also be the same.

Adenine and Thymine are bound by 2 hydrogen bonds

Guanine and Cytosine are bound by 3 hydrogen bonds.

Total number of hydrogen bonds are 3000 as given above.

So, if there are total of 600 Adenines and 600 Guanines, then there would be 600 Thymines and 600 Cytosines to pair with Adenines and Guanines. A total of 2400 nucleotides are present initially.

so, 600 A-T (2 hydrogen bonds) and 600 G-C (3 hydrogen bonds)

600*2= 1200 600*3=1800

Total hydrogen bonds = 3000.

After mutation, there are only 2398 nucleotides. That means, 2 nucleotides are missing. So, it is a Point mutation or more specifically deletion mutation.

gladiator answered 2 years ago

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