Question

Part A:
A balloon, whose volume at 23° C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is the volume of the balloon at 46° C?

Part B:
A sealed container filled with argon gas at 35° has a pressure of 832 torr. If the volume of the container is decreased by a factor of two, what will happen to the pressure (increase or decrease)? Will it be by a factor of two? You may assume the temperature remains at 35° C.

Answer 1

V1= 535 ml

T1 = 23 +273 K = 296K

V2 = ?

T2 = 46�C = 319 K

When P constnat (suppose that) apply ideal gas then:

V1/V2 = T1/T2

V2 = V1*T2/T1

V2 = 535 ml * (319//296) = 576 ml

V2 = 576 ml

B)

T1 = 35�C = 308 K

P1 = 832 torr

V1 = ?

T2 = T1 constant

P2 = ?

V2 = 1/2 of V1

Use Ideal gas Law

P1V1 = P2V2

P2 = P1*(V1/V2)

P2 = 832 torr * (V1 / (0.5 V1)) = 832 /2 = 416 torr

P2 = 416 torr