Part A A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C)....

Part A

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If the final temperature of the system is 21.00 ∘C , what is the mass of the steel bar?

Use the following values:

specific heat of water = 4.18 J/(g⋅∘C)

specific heat of steel = 0.452 J/(g⋅∘C)

please show work

Part B

The specific heat of water is 4.18 J/(g⋅∘C). Calculate the molar heat capacity of water?

Expert Solution

queen_honey_blossom answered 2 years ago

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