Question

A balloon at 30.0°C has a volume of 222 mL. If the temperature is increased to 64.1°C and the pressure remains constant, what will the new volume be, in mL?

Answer 1

Answer -

Given,

Initial Temperature = 30.0 C or 303.15 K [°C + 273.15 = K]

Initial Volume = 222 mL or 0.222 L [1 mL = 0.001 L]

Final Temperature = 64.1 C or 337.25 K [°C + 273.15 = K]

Pressure is constant

Final Volume = ?

We know that,

PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = Moles

R = Gas Constant (0.082057 Latm/molK)

Put the initial conditions,

PV = nRT

P * 0.222 L= n * (0.082057 Latm/molK) * 303.15 K

P * 0.222 L= n * 24.87558 Latm/mol

P/n = 24.87558 Latm/mol / 0.222 L

P/n = 112.0522 atm/mol ------------------1

As the Pressure and moles both are same. So, Put 1 and new Temperature in A,

PV = nRT

(P/n) * V = R*T

So,

112.0522 atm/mol * V = (0.082057 Latm/molK) * 337.25 K

112.0522 atm/mol * V = 27.67372325 Latm/mol

V = 27.67372325 Latm/mol / 112.0522 atm/mol

V = 0.246971 L

Now,

1 L = 1000 mL

So,

0.246971 L = 0.246971 * 1000 mL

So,

0.246971 L = 246.97 mL

So,

New Volume = 246.97 mL [ANSWER]