Question

1) A gas sample has a volume of 151 mL at 0.00 ∘C. The temperature is raised (at constant pressure) until the volume reaches 222 mL . What is the temperature of the gas sample in ∘C at this volume?

2) The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 ∘C.
What would happen to the pressure if the volume were reduced to 0.4 L and the temperature increased to 250 ∘C?

Answer 1

1) P1V1 /T1 = P2V2 /T2 as pressure is constant

V1/T1 = V2/T2

V1 = 151 mL = 0.151 L , T1 = 0⁰C = 273K

V2 = 222 mL = 0.222 L , T2 =?

T2 = (V2T1) / V1 = (0.222 x 273) / 0.151

T2 = 401.4 K = 128.4⁰C

2) P1V1 /T1 = P2V2/T2

P1 = 1.0 atm , V1 = 1.0L , T1 = 25⁰C = 298 K

P2 = ? , v2 = 0.4 L , t2 = 250⁰c = 523 k

P2 = (P1V1T2) / T1V2

P2 = (1.0 x 1.0 x 523) / (298 x 0.4) = 523 / 119.2

P2 = 4.39 atm