In: Chemistry
Show the calculation of the new temperature of a gas sample has an original volume of 740 ml when collected at 710 mm and 35oC when the volume becomes 460 ml at 1.20 atm.
initial final
P1 = 710mm = 710/760 = 0.934atm P2 = 1.2atm
V1 = 740ml V2 = 460ml
T1 = 35+273 = 308K T2 =
P1V1/T1 = P2V2/T2
T2 = P2V2T1/P1V1
= 1.2*460*308/0.934*740 = 245.98K