The Henry's law constant for helium gas in water at 30°C is 3.70 x10-4 M/atm.

The Henry's law constant for helium gas in water at 30°C is 3.70 x10^-4 M/atm. If the partial pressure of helium above a sample of water is o.650 atm, what is the concentration of helium in water?

A. 5.69 x10^-4 M B. 1.76 10³ M C. 1.30 M vD. 2.41 x10^-4 M

Expert Solution

henry's law constant k_H = 3.70 x 10^-4 M / atm

partial pressure of He = 0.650 atm

concentration = k_H x P

= 3.70 x 10^-4 x 0.650

= 2.41 x 10^-4 M

concentration = 2.41 x 10^-4 M

queen_honey_blossom answered 2 years ago

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